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valentinak56 [21]
3 years ago
7

Set up and evaluate the optimization problem. You are constructing a cardboard box from a piece of cardboard with the dimensions

4 m by 8 m. You then cut equal-size squares from each corner so you may fold the edges. What are the dimensions (in m) of the box with the largest volume

Mathematics
1 answer:
ankoles [38]3 years ago
5 0

Answer:

Shorter\ side=4-2\times 0.845=2.31\ m\\Longest\ side=8-2\times 0.845=6.31\ m\\Height=0.845\ m

Step-by-step explanation:

Given that , dimension of the cardboard is 4 m by 8 m.

Lets the dimensions of the square is x m by x m.

The volume after cutting the equal size of square from all the four corners is given as

V=x\times (4-2x)\times (8-2x)\\V=x\times (32-16x-8x+4x^2)\\V=x\times (4x^2-24x+32)\\V=4x^3-24x^2+32x\\

For the maximum volume

\dfrac{dV}{dx}=12x^2-48x+32=0\\3x^2-12x+8=0\\

For maximum value of volume , the value of x will be 0.845

x= 0.845

Therefore the dimensions will be

Shorter\ side=4-2\times 0.845=2.31\ m\\Longest\ side=8-2\times 0.845=6.31\ m\\Height=0.845\ m

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