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Tanya [424]
3 years ago
15

Do not answer until you see an image.

Mathematics
1 answer:
mezya [45]3 years ago
3 0
From least to greatest is -0.52, 1/5, 5/16, 3/4, 0.90.
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When an exponential expression is raised to another exponent the exponent is______​
goldenfox [79]

Answer:

Step-by-step explanation:

When raising a power to a power in an exponential expression, you find the new power by multiplying the two powers together. For example, in the following expression, x to the power of 3 is being raised to the power of 6, and so you would multiply 3 and 6 to find the new power.

3 0
3 years ago
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Find the area of the shaded region to the nearest tenth.
Murrr4er [49]

Answer:

(540-36π)km²

Step-by-step explanation:

First solve the area of the shaded triangle. 40 times 27 divided by 2 equals 540. Now subtract the area of the circle. The area of the circle is 36π because the radius is 6 and 6 squared times pi equals 36π. Finally subtract 36π from 540. The answer is (540-36π)².

3 0
3 years ago
Please help I will mark previous
yawa3891 [41]

Answer:

Im sorry! idk the answer but if you have a phone, there is this app called photo math, or ask you mom or dad for help.

Step-by-step explanation:

8 0
3 years ago
What is the probability that I will choose the 5 students with the highest grades from my class of 35?
iris [78.8K]
I think it’s a 5 percent chance because you only have one 5th student
3 0
3 years ago
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Find the quotient and remainder when p (x) divides with g (x) question (i) P (x) = x raise to 4 - 3 x square +4x + 5, g (x) = x
Morgarella [4.7K]

Answer:  x^2-8+\dfrac{4x+5}{x^4-3x^2+4x+5}

<u>Step-by-step explanation:</u>

P(x) = x⁴ - 3x² + 4x + 5

g(x) = x² + 5

         <u>_x²_- 8                           </u>

x² + 5) x⁴ + 0x³ - 3x² + 4x + 5

        -<u>(x⁴ + 0x³ + 5x²) </u>  ↓     ↓  

                         -8x² + 4x  + 5

                       -<u>(-8x² + 0x - 40)</u>

                                    4x + 45

\dfrac{x^4-3x^2+4x+5}{x^2+5}=\large\boxed{x^2-8+\dfrac{4x+5}{x^4-3x^2+4x+5}}

5 0
4 years ago
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