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Delicious77 [7]
3 years ago
13

A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standa

rd deviation were calculated. Based on the results, the exams created claims that on the same exam,same exam, nine times out of ten, seniors will have an average score within 5% of 71%.
Is the confidence interval at 90%, 95% or 99%? What is the margin of error? Calculate the confidence interval and explain what it means in terms of the situation.
Mathematics
1 answer:
Lilit [14]3 years ago
3 0

Answer:

Step-by-step explanation:

sheeeeeesh

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Answer:

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Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

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Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

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jasenka [17]
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I sold 178 tickets, each ticket costs 12 dollars, how much money did I get?
laiz [17]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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