1. are angles 2, 3, and 7
2. is x=42, y=138
3. x=65, y=65
4. d=135 h=135 e=135 b=45 c=45 g=45 f=45
Answer:
Step-by-step explanation:
<h3>
Algebraic Identities:</h3>
Identity used: (a +b)³ = a³ + b³ + 3ab(a +b)
p + q = -2 ------------------(I)
Both sides take cube,
(p +q)³ = (-2)³
a = p and b =q
p³ + q³ + 3pq(p +q) = -8
p³ + q³ + 3pq*(-2) = - 8 {From (I)}
p³ + q³ - 6pq = -8
p³ + q³ = -8 + 6pq
p³ + q³ + 8 = 6pq
Hence, proved.
Answer:
x = 42.9 m
Step-by-step explanation:
Corresponding sides of similar triangles MAB and MNP are proportional. This means ...
x/MP = MA/MN
However, we don't have a number for MA yet, so we need to find it.
MA +AN = MN
MA = MN - AN subtract AN
MA = 67.2 m - 32 m = 35.2 m
Now, we can use this to find x.
x = MP · (MA/MN) = (81.9 m) · 35.2/67.2
x = 42.9 m
Answer:3(7n+6)(3-5)
Step-by-step explanation:
9514 1404 393
Answer:
85.7 meters
Step-by-step explanation:
A graphing calculator finds the result easily. The ball moved 85.7 meters horizontally before it hit the hill.
__
Equating y expressions gives ...
0.725x = -0.05x^2 +5x +1
In standard form, this is ...
0.05x^2 -4.275x -1 = 0
The quadratic formula tells us the positive solution is ...
x = (4.275 +√(4.275^2 -4(0.05)(-1)))/(2(0.05)) = (4.275 +√18.475625)/.1
x ≈ 85.733
The cannon ball hits the hill at a horizontal distance of 85.7 meters from the cannon.