The scale factor from A to B is 5/3 and the value of r is 33/5
<h3>The scale factor from A to B</h3>
From the figure, we have the following corresponding sides
A : B = 5 : 3
Express as fraction
B/A = 3/5
This means that, the scale factor from A to B is 5/3
<h3>The value of r</h3>
From the figure, we have the following corresponding sides
A : B = 11 : r
Express as fraction
B/A = r/11
Recall that:
B/A = 3/5
So, we have:
3/5 = r/11
Multiply by 11
r = 33/5
Hence, the value of r is 33/5
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Answer: 2
Step-by-step explanation:
−y + 25 = 12y − 1
Переместите все члены, содержащие y, в левую часть уравнения
Вычтем 12y из обеих частей уравнения.
−y + 25 − 12y = −1
Вычтем 12y из −y.
−13y + 25 = −1
Переместите все члены, не содержащие y, в правую часть уравнения.
Вычтем 25 из обеих частей уравнения.
−13y = −1 − 25
Вычтем 25 из −1.
−13y = −26
Разделите каждый член на −13 и упростите.
Разделите каждый член в −13y = −26 на −13.
−13y
/-13 = -26/-13
Сократить общий множитель −13.
−26
/-13
Разделим −26 на −13.
y = 2
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Correlation Coefficient (r) = 0.989
alph=0.05
Number of observations (n) = 8
determine if there is a linear correlation between chest size and weight.
Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.
What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.
r^2 = square of the correlation Coefficient
r^2 = 0.989^2 = 0.978121
Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.
