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Norma-Jean [14]

2 years ago

12

(1+sinA+cosA)^2 = 2(1+sinA) (1+cosA)

1 answer:

statuscvo [17]2 years ago

5 0

Answer:

Step-by-step explanation:

$L.H.S = 1^2+Sin^2A+Cos^2A+2SinA+2CosA+2SinACosA\\ \{(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca\}\\ = 1 + (Sin^2A+Cos^2A) + 2SinA+2CosA+2SinACosA \\ \{Sin^2A+Cos^2A=1\}\\ = 1 + 1 + 2SinA+2CosA+2SinACosA \\ = 2(1 + SinA+CosA+SinACosA)\\ = 2(1^2 + (SinA+CosA).1+ SinACosA )\\ \{x^2+(a+b)x + ab = (x+a)(x+b)\} \quad here \quad x=1\\ = 2(1+SinA)(1+CosA).\\$

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Katie has $50 in a saving account at the beginning of the summer. She wants to have at least $20 in the account by the end of th

RideAnS [48]

She can only withdrawl 30 dollars

6 0

3 years ago

A box has a width of 10 cm and a length of 17 cm. The volume of the box is decreasing at a rate of 527 cubic cm per minute, with

Ber [7]

Answer:

$-3.1$ cm per minute.

Step-by-step explanation:

We have been given that a box has a width of 10 cm and a length of 17 cm. The volume of the box is decreasing at a rate of 527 cubic cm per minute, with the width and length being held constant.

We know that volume of a cuboid is length times width times height.

$V=lwh$

Upon substituting our given width and length, we will get:

$V=17\cdot 10\cdot h$

$V=170\cdot h$

Now, we will find derivative of volume with respect to time as:

$\frac{dV}{dt}=170\cdot \frac{dh}{dt}$

Since the volume of the box is decreasing at a rate of 527 cubic cm per minute, so we will substitute $\frac{dV}{dt}=-527$ as:

$-527=170\cdot \frac{dh}{dt}$

$\frac{-527}{170}=\frac{170\cdot \frac{dh}{dt}}{170}$

$\frac{dh}{dt}=-3.1$

Therefore, the rate of change in height is $-3.1$ cm per minute.

6 0

4 years ago

Round 13.2 to a whole number

omeli [17]

13 because decimal is 4 or below let it rest or 5 or more go up one more

8 0

4 years ago

Read 2 more answers

What is the volume of a rectangular prism

dangina [55]

Answer:

30

Step-by-step explanation:

I counted all the squares

7 0

3 years ago

John cut a paper square with a perimeter of 18 inches into two rectangles. The perimeter of one of the rectangles is 10 inches.

Lady_Fox [76]

Answer:

13.5 inches

Step-by-step explanation:

Perimeter of the paper square = 18inches

Perimeter of a square = 4s

4s = 18 inches

s = 18/4 = 4.5 inches

Therefore, each side of the square = 4.5 inches.

When the square is cut into 2 rectangles,

The perimeter of one of the rectangles is 10 inches.

Perimeter of the second rectangle = 2L + 2W

Let the length of the rectangle (L) = one side of the square = 4.5 inches

Width of the Rectangle = Length of the square/2 = 4.5 inches/ 2 = 2.25

Perimeter of the second rectangle = 2(4.5) + 2(2.25)

= 9 + 4.5

= 13.5 inches

4 0

3 years ago