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Lady_Fox [76]
3 years ago
13

Convert 0.5kg to ounces

Mathematics
2 answers:
Marysya12 [62]3 years ago
6 0

Answer:

17.6369809748oz

Step-by-step explanation:

hope this helps

dlinn [17]3 years ago
3 0

Answer:

17.637

Step-by-step explanation:

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What is the difference written in scientific notation? 0.00067 - 2.3 x 10^5
shepuryov [24]
0.00067=67X10^5 so

67X10^5-2.3X10^5

64.7X10^5 which can be expressed as:

6.47X10^6

(not sure if it matters to you or not, but technically we only had two significant figures so it should be rounded to 6.5X10^6)


5 0
4 years ago
Please help me IDK how to do this!!!!!!
tatiyna
A parallelogram should have 2 sets of parallel lines. Let's find the slope of line PQ and RS to test.

PQ:
(4-2)/(1-(-3))
2/4
1/2

RS:
(2-0)/(3-1)
2/2
1

Because 1 does not equal 1/2 (the slopes are different) the lines are not parallel. Thus, the figure is not a parallelogram.
5 0
3 years ago
Abby, Bik, Cari, Dawn, and Ellen collect T-shirts. Abby has the most. Bik has 2.5 times as many T-shirts as Cari. Dawn has 1/3 a
bixtya [17]
A=abby's shirts
b=bik's shirts
c=cari's shirts
d=dawn's shirts
e=ellen's shirts


a> everybody
b=2.5c
d=(1/3)c
a+b+c+d=120
e=2d+1
e=13
oook

e=13=2d+1
13=2d+1
12=2d
d=6

d=(1/3)c
6=(1/3)c
18=c

b=2.5c
b=2.5(18)
b=45

a+b+c+d=120
a+45+18+6=120
a+69=120
a=51
4 0
3 years ago
Answer??????????????????????
ch4aika [34]
Here is the answer you are looking for: (7,13/3)

Please vote my answer brainliest. thanks!
5 0
3 years ago
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
2 years ago
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