3x=4 1/2 divide each side by 3
1 answer:
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Answer: 2 seconds.
Step-by-step explanation:
Given : A ball is thrown upward with an initial velocity of 16 ft/sec from a height of 32 ft above the ground.
The height, in feet, of the ball t sec after it is thrown can be represented by
When ball reaches the ground , s= 0.
Divide both sides by 16 , we get
But time cannot be negative , so t= 2.
Hence , it will take 2 seconds for the ball to reach the ground.
Answer:
Therefore after 1 second of lunched the object reach a height of 16 feet.
Step-by-step explanation:
When a particle is thrown vertically upward direction on that time only gravitation force is worked on it. In that case the acceleration of the particle is - g.Since gravitation force works downward direction and the displacement of the particle is upward direction that's why acceleration is negative.
When particle comes down the the acceleration of the particle is g.
Since the displacement and acceleration work on the particle in same direction.
The value of g is 9.8 m/s².
Given that, the height of the particle can measure from the equation
Where t is time in second
To find out the time when the object reach a height 16 feet. We have put the value of h in the given equation.
Putting h=16 in the given equation
16= -16 t²+32
⇒16t²-32t+16=0
⇒16(t²-2t+1)=0
⇒t²-2t+1=0² [ ∵16≠0]
⇒(t-1)²=0
⇒t-1=0
⇒t=1
Therefore after 1 second of lunched the object reach a height of 16 feet.