Answer: 40.2t - 25
Step-by-step explanation:
-0.2t - 5 (-8t + 5)
-0.2t + 40t -25
39.8t - 25
Answer: 1.10
Work: 5 or more raise the next digit, 4 or less keep it
Answer:
-24.8 m/s
Step-by-step explanation:
Given:
y₀ = 60 m
y = 40 m
v₀ = 15 m/s
a = -9.8 m/s²
Find: v
There are three constant acceleration equations we can use:
y = y₀ + v₀ t + ½ at²
v = at + v₀
v² = v₀² + 2a(y − y₀)
We aren't given the time, so we need to use the third equation, which is independent of time:
v² = v₀² + 2a(y − y₀)
Plug in the values:
v² = (15 m/s)² + 2(-9.8 m/s²) (40 m − 60 m)
v² = 617 m²/s²
v ≈ ±24.8 m/s
Since the coin is on the way down, the velocity is negative. So v = -24.8 m/s.
Given :
Length of parade , 
.
Breadth of parade , 
.
5 people can fit into a 
area.
1 mile = 5280 ft .
To Find :
The size of the crowd.
Solution :
Area of parade ,
Also , 5 people can fit in area .
So , number of people fit in A is :
Therefore , 95040 can fit in the parade .
Hence , this the required solution .
Answer:
4+p
Step-by-step explanation:
