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Ratling [72]
1 year ago
10

Surface area of cone below diameter AB is 20 and distance from B to C is 10

Mathematics
1 answer:
timofeeve [1]1 year ago
4 0

It is given that the diameter of the base of the cone is AB=20, and the slant height is BC=10.

Recall that the radius is one-half of the diameter, it follows that:

r=\frac{1}{2}\cdot20=10

Note that the radius (r), vertical height (h), and slant height (l) of a cone form a right triangle which satisfies the Pythagorean Theorem:

h^2+r^2=l^2

Substitute r=10 and l=10 into the equation:

\begin{gathered} h^2+10^2=10^2 \\ \Rightarrow h^2=10^2-10^2 \\ \Rightarrow h^2=0 \\ \Rightarrow h=0 \end{gathered}

Notice that the height of the cone is calculated to be zero which is not possible for a cone.

The Surface Area of a cone is:

S=\pi r^2+\pi rl

Substitute r=10 and l=10 into the formula:

\begin{gathered} S=\pi(10^2)+\pi(10)(10) \\ \Rightarrow S=100\pi+100\pi=200\pi\text{ square units} \end{gathered}

The answer is 200π square units.

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a. Check the attached image

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3 years ago
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6x+3y=33..........(1)

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substitute value of y from (2) in (1)

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distribute 3 over the bracket

6x+45-12x =33

-6x=33-45

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plugging this value of x in equation 2 we get

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