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AnnZ [28]
3 years ago
12

−14a−(−48a) mind helping

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer:

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

Step-by-step explanation:

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

MrRa [10]3 years ago
7 0

Answer:

34a

Step-by-step explanation:

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Given circle P with arc AE=53, arc BA=68 and arc CB=72 match the following angles with their corresponding measurements
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From the diagram;
1. Angle 2 = ADB+BDH
                                           = arcAB/2 +90 
                                           = 34 +90 
                                           = 124°

2. Angle 4= 90°,
Reason ; the angle between a tangent and a radius is equal to 90. A tangent is a line that touches the circumference of a circle once even if prolonged.

3. Angle 5 = 90 -BDC (note the acr subtends twice the angle it subtends on the circumference to the center.
             = 90-arc BC/2
             = 90-36
              = 54°

4. Angle 6 = BFD
             = 180-ADB-FBD
             = 180-AB/2-DE/2
             But DE = 180 -121 = 59
Therefore, BFD = 180 -34-29.5
             = 116.5°

5. Angle 1 = 180- BFD (angles on a straight line add up to 180°)
              = 180- 116.5
              = 63.5°
           

6. Angle 3 = 180 -(ADB+BFD)
             = 180 -(34 +116.5)
             =  180- 150.5
             = 29.5°
similarly angle 3 = DE/2 = 59/2 = 29.5°

7. Angle 8= 90, because BD is diameter;
 angles subtended by a diameter to the circumference is always a right angle (90°)


8.Angle 7 =  BE
               but BE= AB+AE
                          = 68+ 53
                          = 121°
                 


    
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