2 years ago

−14a−(−48a) mind helping

2 answers:

8 0

Answer:

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

Step-by-step explanation:

\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}

MrRa [10]2 years ago

7 0

Answer:

34a

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The sum of the percentages must be 100%.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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raketka [301]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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saul85 [17]

Answer:

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Step-by-step explanation:

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