Something's not quite right here. What do you mean by "N?"
I could and will make assumptions regarding what you meant. (Feel free to correct me if need be.)
Find the equation of a line through (0,2) <span>which is perpendicular to the line y=3x+3. To find the slope of this perpendicular line, take the negative reciprocal of 3 (the slope of the given line). It is -1/3.
Using the point-slope form of the equation of a straight line:
y = (-1/3)x + 2 (answer)</span>
7 x 7
2 + 47
56 - 7
Hope you needed this!
I am not sure what you mean, but x=4
Answer:
1. -7.5
2. $1
3. 40
Step-by-step explanation:
For number 1, it can be solved by using the PEMDAS method, or see explanation below:
6x - 4x - 36 = 6 - 2x
2x - 36= -2x + 6
4x + 36 = 6
4x = -30
x = -15/2 or -7.5
For number 2, substitute 3 into both equations:
f(x) =1.50(3) + 2.00
and
f(x) = 2.00(3) + 1.50
This would get $6.50 and $7.50, which, if subtracted, gets $1.
For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.
Hope this helps!