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Tanzania [10]
4 years ago
6

Question 1. What is the acceleration if the initial velocity was 5 m/s, the final

Physics
1 answer:
Nikolay [14]4 years ago
5 0

Answer:

a = 5m/s²

Explanation:

a = (v - u)/t

a = (20 - 5)/3

a = 15/3

a = 5m/s²

pls give brainliest

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Olegator [25]
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3 years ago
15. A locomotive moved 18.0 m [W] in a time of 6.00 s and stopped. After stopping, the
mariarad [96]

Answer:

Distance = 30m

Displacement = 6m W

Explanation:

Given the following:

Movement 1 = 18m W

Movement 2 = 12m E

Diatance is a scalar quantity with only magnitude and no direction. That is, in Calculating the distance moved by the locomotive, the direction of travel or movement of the object is not considered. It only measures the total amount of movement made during the Time of motion.

Therefore, total distance traveled equals :

Movement 1 + movement 2

18m + 12m = 30m

B) Displacement also measures the movement made by an object. However, Displacement is a vector quantity and therefore, considers both magnitude and direction of travel of the object. Therefore, it measures the overall change in position of the object from its starting position.

Therefore, Displacement of the locomotive equals:

18m W - 12m E = 6m E

3 0
3 years ago
A Stegosaurus hits' a wall with a force of
Pavel [41]

Answer: a= -1.9 m/s²

Explanation: F = ma and a = F / m = 60 N / 32 kg = 1.875 m/s²

Because of law of action and reaction, wall applies same force to dino

In opposite direction and Dino is decelerating. Thus sign Is negative.

3 0
3 years ago
During which segments are two states of matter present?
dezoksy [38]

Answer:

the correct answer is D.) 2,4

3 0
4 years ago
the book has a mass of 2.5 kg. What net force must act on the book to mak it accelerate to the left at a rate of 7.0m/s2?
Reil [10]

Answer:

17.5 N

Explanation:

<h2>Given :</h2>

  • Mass (m) = 2.5 kg
  • Acceleration (a) = 7.0 m/s²

<h2>To calculate :</h2>

  • Force exerted (F)

<h2>Calculation :</h2>

<h3>• F = ma</h3>

→ F = (2.5 × 7.0) N

→ F = 25/10 × 7 N

→ F = 5/2 × 7 N

→ F = (5 × 7)/2 N

→ F = 35/2 N

→ <u>F</u><u> </u><u>=</u><u> </u><u>1</u><u>7</u><u>.</u><u>5</u><u> </u><u>N</u><u> </u><u>towards</u><u> </u><u>left</u>

Hence, 17.5 N of net force must act on the book to make it accelerate to the left.

5 0
3 years ago
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