Answer:
The speed of light is that medium is 281907786.2 m/s.
Explanation:
since the critical angle is Фc = 430, we know that the refractive index is given by:
n = 1/sin(Фc)
= 1/sin(430)
= 1.06
then if n is the refractive index of the medium and c is the speed of light, then the speed of light in the medium is given by:
v = c/n
= (3×10^8)/(1.06)
= 281907786.2 m/s
Therefore, the speed of light is that medium is 281907786.2 m/s.
Answer:
Change in Potential energy, pe = Final potential energy - Initial potential energy
Explanation:
∆p.e = Final p.e - Initial p.e
From the equation ∆p.e = (mgh) final - (mgh) initial
Answer: 6.12metres
Explanation:
The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ
Recall that Wavespeed (V) = Frequency F x wavelength λ
V = F λ
In this case,
Wavespeed of sound = 1530 m/s
Frequency of sound = 2.50 x 10^2 Hz
Wavelength = ? (let the unknown value be Z)
Apply V = F λ
1530 m/s = 2.50 x 10^2 Hz x Z
Z = (1530 m/s / 2.50 x 10^2 Hz)
Z = (1530 m/s / 250Hz)
Z = 6.12m
Thus, the wavelength of sound in sea water is 6.12m
60.3° from due south and 5.89 m/s For this problem, first calculate a translation that will put John's destination directly on the origin and apply that translation to Mary's destination. Then the vector from the origin to Mary's new destination will be the relative vector of Mary as compared to John. So John is traveling due south at 6.7 m/s. After 1 second, he will be at coordinates (0,-6.7). The translation will be (0,6.7) Mary is traveling 28° West of due south. So her location after 1 second will be (-sin(28)*10.9, -cos(28)*10.9) = (-5.117240034, -9.624128762) After translating that coordinate up by 6.7, you get (-5.117240034, -2.924128762) The tangent of the angle will be 2.924128762/5.117240034 = 0.57142693 The arc tangent is atan(0.57142693) = 29.74481039° Subtract that value from 90 since you want the complement of the angle which is now 60.25518961° So Mary is traveling 60.3° relative to due south as seen from John's point of view. The magnitude of her relative speed is sqrt(-5.117240034^2 + -2.924128762^2) = 5.893783 m/s Rounding the results to 3 significant digits results in 60.3° and 5.89 m/s
Gamma rays are found in extremely hot regions and they have the smallest wavelength but the most energy. They can be found by the effects they have on matter and it do few basic things with matter, it can collide with a electron and bounce of it as a billiard ball.
