Answer:
A. 1.172 metres
B. 6.82 Ns
C. 4.796 m/s
Explanation:
The total initial momentum is gotten by multiplying the mass and initial velocity of the both bodies.
The 1.40 kg block is at rest so velocity is zero and has no momentum.
The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s
Momentum = 310*0.022
Momentum = 6.82 Ns.
If the bullet gets embedded they will both have common velocity v
6.82 = (0.022+1.40)v
6.82 = 1.422v
V = 6.82/1.422
V = 4.796 m/s
How high the block will rise after the bullet is embedded is given by
H = (U²Sin²tita)/2g
Where tita is 90°
H = (4.796² * sin²(90))/(2*9.81)
H =( 23.001616*1)/19.62
H = 1.172 metres
Answer: 
Explanation:
The <u>Heisenberg uncertainty principle</u> postulates that the fact each particle has a wave associated with it, imposes restrictions on the ability to determine its position and speed at the same time.
In other words:
It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle. Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.
Mathematically this principle is written as:
(1)
Where:
is the uncertainty in the position of the electron
is the Planck constant
is the mass of the electron
is the uncertainty in the velocity of the electron.
If we know the accuracy of the velocity is
of the velocity of the electron
, then
is:


(2)
Now, the least possible uncertainty in position
is:
(3)
(4)
Finally:
the ball will stay moving at the same rate of speed until something happens and stop it
Answer:
C₁ = 3 pF
C₂ = 6 pF
Explanation:
Let the capacitance be C₁ and C₂.
For parallel combination
C₁ +C₂ = 9
For series combination


C₁ X C₂ = 18
( 9-C₂ )X C₂ = 18
C₂²- 9C₂ +18 = 0
C₂ = 6 or 3.
C₁ = 3 or 6.
C₁ = 3 pF
C₂ = 6 pF