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Romashka-Z-Leto [24]
3 years ago
11

If a right isosceles triangle has an area of 192 cm, what is the height of the triangle?

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

40

Step-by-step explanation:

Lina20 [59]3 years ago
5 0

Answer: if the base is 24

Area = (base x height)/2, thus height = 2 (area/base)                

height = 2(192/24)

Which gives you 40

height = 16 cm

the height and half of the base will give you two identical rightangle halves of the triangle

use pythagorean theorem to get the length of the hypotenuse of the 2 identical halves

a^2 + b^2 = c^2

12^2 + 16^2 = c^2

144 + 256 = c^2

(square root)400 = c

20 cm = c

there are 2 of these hypotenuses in the original triangle, so add the base and the 2 "hypotenuses" to get the perimeter

P = 20 + 20 + 24  

P = 64 cm

****the perimeter of the isosceles triangle is 64cm

Step-by-step explanation:

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allochka39001 [22]
Recall that all three angles in a triangle equals 180.
Knowing this, we just have to add up all the angles and figure out what the value 'x' is.

(x-22 + x-17 + 3x+19) = 180
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Divide both sides by 5:
x = 40

Now that we found the value for x, we need to solve for angle A.
Simply input the value of 'x' into angle A's equation:
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Angle A = 18 degrees

Good luck! If you need me to explain anything, just ask :))
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