Answer:
the answer is c.
Step-by-step explanation:
Answer: The required ratio is 1:1.
Step-by-step explanation:
Let the total number of CDs be 100
of CDs is given by

According to question,
of her Jazz CDs represents
of all her CDs.
Let the number of Jazz CDs be x
So, it becomes

So, Number of Jazz's CDs is 50
Number of Jazz non CDs is given by

Ratio of her CDs to her non- CDs is given by

Hence, the required ratio is 1:1.
Answer:
Cleanser that costs 50 cents is 1400 liters, Cleanser that costs 80 cents is 600 liters.
Step-by-step explanation:
We can solve this by using <em>simultaneous equations</em>:
- Let us express the question in terms of equations
Let a be cleanser at 50 cents and let b be the cleanser at 80 cents.
Equation 1: 0.5a + 0.8b = 0.59(a+b)
Equation 2: a + b = 2000
From equation 2, a = 2000 - b (Let's call this equation 3)
2. Substituting equations 2 and 3 in Equation 1:
0.5a + 0.8b = 0.59(a+b)
0.5(2000 - b) + 0.8b = 0.59(2000)
1000 - 0.5b + 0.8b = 1180
0.3b = 180
b = 600
Substitute in equation 3:
a = 2000 - 600
a = 1400
As a note, I formed equation 1 because I know for a fact the cost per liter of a and b. I also know it is sold at 0.59 cents per liter. We are selling 2000 liters in this instance, therefore 0.59(2000) = 1180, which in this case is the selling price.
Answer
12
Step-by-step explanation
there is 15 of each color 3 take away 15 equals 12 red skittles left
8775
/ \
3 2925
/ \
3 975
/ \
3 325
/ \
5 65
/ \
5 13
/ \
13 1
Prime Factors: 3, 3, 3, 5, 5, 13