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Rainbow [258]
3 years ago
5

Your friend is on a weight loss program and has a goal of loosing 15 pounds. So far she has lost 3.5 pounds in the first two wee

ks. If she keeps up this rate of weight loss, how long can she expect it to take her to meet her weight loss goal?
Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Lets do the math together.

3.5/2 to find the weight loss per week= 1.75.

We know that every week the friend will reduce her goal by 1.75.

15/1.75= 8.6.

This means that in 8.6 weeks the friend will lose 15 pounds.

I hope this Helps! :)

mojhsa [17]3 years ago
5 0

Hello there! It should take her 8.6 weeks.

Well, the question doesn't specify whether it wants how long it'll take her in weeks, months, or days, so let's go with weeks. To do this, find the unit rate by dividing the amount she lost by the number of weeks it took.

3.5 pounds ÷ 2 weeks = 1.75 pounds lost a week.

Now, divide the total she wants to loose (15 pounds) by the 1.75 pounds a week to see how many she looses in total.

15/1.75 = 8.57142... Which is a little over 8.5 weeks, so we can round up to 8.6 weeks.

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Ricardo purchased a new car with special 1.9% financing. If the cars price was 17,999 and he financed it for years, find his mon
frosja888 [35]

Answer:

the answer is actually $389.71

Step-by-step explanation:

4 0
3 years ago
I need help I don’t understand and I need to show my work who would help me??
stich3 [128]

Answer: b

Step-by-step explanation:

In the last question, you wrote on a second equation "13x ...." kkk

Let's go:

We have to check each one answer in the following system:

x - 2y = 7

3x + 7y = 8

I can use the substituition method to solve this system...

x = 7 + 2y

3x + 7y = 8

3(7 + 2y) + 7y = 8

21 + 6y + 7y = 8

13y = 8 - 21

13y = -13

y = -1

x = 7 + 2.(-1)

x = 5

Finally, the correct answer is the second one (letter b).

5 0
3 years ago
Read 2 more answers
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
PLEASE HELP!!! 20 POINTS WILL BE GIVEN!
77julia77 [94]
SI = PRT /100

1. SI = 400*5*1/100
        = 2000/100
        = $ 20

2. SI = 1000*8.5*3/100
        = 25.5*1000/100
        = $ 255

3.  SI = 200*9*1/2*100
         = 900/100
         = $9

4.  SI = 20000*12*3/100
         = 200*12*3
         = 7200

5.  SI = 1200*4.5*6/12*100
         = 4.5*6
         = $27
  
Amount to pay = Principal + SI
                        = 1200+27
                        = $1227 ( But this answer isn't there in the options )

4 0
3 years ago
Read 2 more answers
Five friends are leaving a bar for home. Aside from the owner of the car, one other person is deemed able to operate the vehicle
erastova [34]

Answer:

4

Step-by-step explanation:

one person is deemed to drive and that person is fixed on the driver's seat no mater which arrangement.

we have now 2 more seats one adjacent to the driver and one rear (two combined).

so the total ways in which all five can be arranged is as follows.

driver, adjacent to him(1)  and three back.

driver adjacent to him (different person) and three back.

see the driver is always fixed so we can ignore him.

thus we when driver set fixed , on two remaining seats (adjacent to driver and the back )there can be 4 different combinations.

3 0
3 years ago
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