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insens350 [35]
4 years ago
12

Andy had 6 2/3 cups of juice. How many 2/3-cup servings can he pour?

Mathematics
2 answers:
Angelina_Jolie [31]4 years ago
6 0
Andy can pour 10 2/3 cup servings.
Roman55 [17]4 years ago
4 0

Answer: 10

Step-by-step explanation:

First, you need to change 6 and 2/3 into an improper fraction which is 20/3. Then, you need to divide 20/3 by 2/3 to find your answer. To do this, simply turn 2/3 to 3/2 and multiply it by 20/3. 20/3 x 3/2 = 60/6. 60/6 in simplest form is 10. Therefore, you answer is 10.

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Rectangles JKLM and STUV are similar. The width of JKLM Is 30 feet and the perimeter is 140 feet. The length of STUV is 8 yards.
algol13
Rectangle JKLM:
p = 140 ft
w = 30ft
l = (140 - 2(30))/2 = 40ft
A = (30)(40) = 1200 ft²

Rectangle STUV:
l = 8yd = (8)(3) = 24 ft

24ft/40ft = 3/5

so . .

w = 3/5*30 = 18ft
A = 3/5*1200 = 720 ft²

Ratio of area JKLM:STUV = 1200/720 = 5/3
5 0
3 years ago
Triangle ABC was reflected over line m, then dilated by a scale factor between 0 and 1. Which diagram illustrates these transfor
vova2212 [387]

Answer:

I think its A.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me with vivid explanation​
Ivanshal [37]

Answer:

864 m²

Step-by-step explanation:

  • First calculate the total area of the rectangular field

The area of a rectangle is given by the product of the length and the width

let A be the total area

A = 100*120

A = 12000 m²

Calculate the area of the small rectangles

  • Let A' be the total area of the four small rectangles and A" the area of one small rectangle
  • A' = 4 A"
  • A' = 4 [(\frac{120-4}{2})*(\frac{100-4}{2})]
  • A' = 4*58*48
  • A' = 11136 m²

  • Substract the A' from A to get the area of the road

Let A"' be the area of the road

A"' =A-A'

A"' = 12000-11136

A"' = 864 m²

3 0
3 years ago
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
How do u subtract (3x+5y-4)_(4×+11)
AleksAgata [21]
Distribute the negative sign to the 4x and 11 making it 3x+5y-4-4x-11 and combine like terms 
5 0
4 years ago
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