Rectangle JKLM:
p = 140 ft
w = 30ft
l = (140 - 2(30))/2 = 40ft
A = (30)(40) = 1200 ft²
Rectangle STUV:
l = 8yd = (8)(3) = 24 ft
24ft/40ft = 3/5
so . .
w = 3/5*30 = 18ft
A = 3/5*1200 = 720 ft²
Ratio of area JKLM:STUV = 1200/720 = 5/3
Answer:
864 m²
Step-by-step explanation:
- First calculate the total area of the rectangular field
The area of a rectangle is given by the product of the length and the width
let A be the total area
A = 100*120
A = 12000 m²
Calculate the area of the small rectangles
- Let A' be the total area of the four small rectangles and A" the area of one small rectangle
- A' = 4 A"
- A' = 4 [(
)*(
)] - A' = 4*58*48
- A' = 11136 m²
- Substract the A' from A to get the area of the road
Let A"' be the area of the road
A"' =A-A'
A"' = 12000-11136
A"' = 864 m²
The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years, is 540 grams.
<h3>What is half-life?</h3>
This can be defined as the time taken for half the amount of a radioactive substance to decay.
To calculate the amount of cesium left after 120 years, we use the formua below.
Formula:
- R' = R/(
)............. Equation 1
Where:
- R = Original amount of Cesium
- R' = New amount of cesium
- T = Total time
- t = Half-life
From the question,
Given:
- R = 8640
- T = 120 years
- t = 30 years
Substitute these values into equation 1
- R' = 8640/(
) - R' = 8640/

- R' = 8640/16
- R' = 540 grams.
Hence, The mass of cesium left afer 120 years is 540 grams.
Learn more about half-life here: brainly.com/question/25750315
Distribute the negative sign to the 4x and 11 making it 3x+5y-4-4x-11 and combine like terms