We are given with the data of a parabola with vertex at (2, 2) and directrix at <span>y = 2.5. the formua should be ax^2 + b x + c = y because of the directrix.
(x-h)^2 = 4a (y-k)
(x-2)^2 =4a (y-2)
a is the equidistant distance from focus to vertex and from vertex to directrix that is equal to -0.5
then the answer is
</span>(x-2)^2 =-0.5*4 (y-2)
<span>x2 - 4x + 4 = -2y +4
x2-4x+2y = 0
answer is C
</span>
Answer:
(x, y) = (-6, 0)
Step-by-step explanation:
The y-coefficients have opposite signs, so we can eliminate y-terms by multiplying both equations by a positive number and adding the results.
9 times the first equation plus 4 times the second gives ...
9(5x +4y) +4(3x -9y) = 9(-30) +4(-18)
45x +36y +12x -36y = -270 -72 . . . . eliminate parentheses
57x = -342 . . . . . collect terms
x = -6 . . . . . . . divide by the coefficient of x
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Substituting into the first equation gives ...
5(-6) +4y = -30
4y = 0 . . . . . . . . . add 30
y = 0
The solution is (x, y) = (-6, 0).
Answer:
circle of radius 10 centered at (-2, 0)
Step-by-step explanation:
The equation is of the form ...
(x -h)^2 +(y -k)^2 = r^2
with (h, k) = (-2, 0) and r=10.
This is the standard form of the equation of a circle with radius r centered at (h, k).
See the attached for a graph.
Answer:
Por definición convencional se dirá que cualquier elemento del siguiente conjunto, ℕ = {1, 2, 3, 4, …}, es un número natura