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Nastasia [14]
3 years ago
9

A classmate said that line AB and line DC are parallel based on the diagram below. Explain your classmates error.

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

<em><u>Explanation</u></em>:

The only information we have to go on is that ∠AWZ ≅ ∠XYC. However, these are not specific kinds of angles that can prove lines parallel. If we had a pair of alternate interior angles, such as ∠AWZ and ∠WZY, we could say that the lines are parallel. However, we do not have enough information.

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Answer:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

Step-by-step explanation:

Incomplete question:

<em></em>\angle CBD = 53^\circ<em></em>

<em></em>\angle CAB = 35^\circ<em></em>

<em></em>AB = 75<em></em>

<em></em>

<em>See attachment for complete question</em>

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

\angle ABC + \angle CBD = 180 --- angle on a straight line

\angle ABC + 53= 180

Collect like terms

\angle ABC =- 53+ 180

\angle ABC =127^\circ

\angle ABC + \angle ACB + \angle CAB = 180 --- angles in a triangle

\angle ACB + 127 + 35 = 180

Collect like terms

\angle ACB =- 127 - 35 + 180

\angle ACB =18

Apply sine rule

\frac{\sin A}{a} = \frac{\sin B}{b}

In this case:

\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}

This gives:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

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