Question

Please help on this !!!!!!!!!!! Will mark brainliest answer !!!!!!!!!

Answer 1

Answer:

the smallest r is the 4r and the biggest r is the r^2

VERTEX (-2,-64)

Step-by-step explanation:

Answer 2

Answer:

smaller r = -10

larger r = 6

The ordered pair for the vertex of the parabola is $(-2,-64)$

Step-by-step explanation:

We have the function $f(r)=r^2+4x-60$

In order to factor this quadratic equation, we need to look for two numbers that will

Add together to get 4

Multiply together to get -60

Lets look for the numbers that multiply to give us -60.

-1 and 60

1 and -60

2 and -30

-2 and 30

3 and -20

-3 and 20

4 and -15

-4 and 15

5 and -12

-5 and 12

6 and -10

-6 and 10

Now, we just need to determine which of these numbers will add together to get us 4.

Those two numbers would be -6 and 10.

This means that our factored form of this equation will be

$f(r)=(r-6)(r+10)$

From this, we can find our roots, which are the solutions to the equation when it is equal to 0.

$(r-6)(r+10)=0\\\\r=-10, r=6$

These are our r values.

The vertex of a parabola will always be directly between the two roots.

The number that is between -10 and 6 is $r=-2$

To find the y-value of the coordinate pair, we just need to plug -2 into our function.

$f(-2)=(-2)^2+4(-2)-60\\\\f(-2)=4-8-60\\\\f(-2)=-64$

This means that the ordered pair for the vertex of the parabola is $(-2,-64)$