Answer:
-x^2 - 20x -4 = 0
Step-by-step explanation:
I assume you meant (x-8)(2x+3) = (3x-5)(x+4).
Perform the two indicated multiplications and then combine like terms:
2x^2 + 3x - 16x - 24 = 3x^2 + 12x - 5x - 20
Combine the x terms on each side:
2x^2 - 13x - 24 = 3x^2 + 7x - 20
Subtract 3x^2 from both sides:
-x^2 - 13x - 24 = 7x - 20
Subtract 7x from both sides:
-x^2 - 20x - 24 = -20
Add 20 to both sides:
-x^2 - 20x -4 = 0 This is the desired quadratic equation.
Answer:
C
Step-by-step explanation:
sorry if I'm wrong-
Period of cos(Bx) is 2pi/B
first case, B = 1
Second case, B = 2
so period of 5*cos x is 2pi/1 = 2pi
period of cos 5x is 2pi/5
hope this help
First convert it into a table of values with independent values being the term number and the dependent values being the actual term.
