Answer:

Step-by-step explanation:
The logistic differential equation is as follows:

In this problem, we have that:
, which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.
At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.
This means that
when
. With this, we can find r, that is, the growth rate,
So




So the differential equation is:


$52/(100-15)=$0.6117 is 1 percent of the price
$0.6117*100=$61.17
Last week the price of the shoes was $61.17
Answer:
7 miles
Step-by-step explanation:
a mile each day so in a week that is 7 days he will swim 1×7 equals 7miles
I'm so sorry but I can't help you with this problem
Answer:
89 km
Step-by-step explanation:
a^2+b^2=c^2
80^2+39^2=c^2
6400+1521=c^2
7921=c^2
sqrt of 7921=89