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LuckyWell [14K]
3 years ago
12

The daily number of patients visiting a dentist's office during one week are 8, 41, 35, 39, 36, and 42.

Mathematics
2 answers:
umka21 [38]3 years ago
6 0

Answer: The median is the only appropriate measure of center

oksian1 [2.3K]3 years ago
6 0

For those of you who are doin the test rn here are the answers to all of them.

Hope this helps! ;)

I did the quiz

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What is the answer to -x/3_>5
den301095 [7]

Answer: this is the answer

( {x}^{3} ) {}^{ - 5}  =  {x}^{ - 15}

Step-by-step explanation:

4 0
3 years ago
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VW | UX. Find UY 20 39 X 26 w​
Lorico [155]

Answer:

39?

Step-by-step explanation:

Because the distance between U and Y is 39.

(I'm sorry if I was wrong)

7 0
2 years ago
Among 1,200 Chinese tourists who are visiting Nepal,45 of them already visited India,40 have visited Pakistan and 15 have visite
SOVA2 [1]

30 visited nepal only 25 visited Pakistan only. 15 tourists at the intersection of the two circles and 1130 have not visited either

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3 years ago
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Help me a soon as possible I need your help help help please as soon as possible ASAP
evablogger [386]

Answer:

B

Step-by-step explanation:

The answer is b because the lines outside -65 are symbols for absolute value. Absolute value means the distance away from 0, so b would be an appropriate choice.

5 0
3 years ago
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If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
2 years ago
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