I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
Answer:
-8
Step-by-step explanation:
-8m⁴ n⁴
m = 0.5 = 1/2
n = 2
Substitute
-8 * (1/2)⁴ * (2)⁴
-8 * (1/16) * (16)
-8
Answer:
The slope (m) = 1/3 and the y-intercept (b) = -4
Label the given points as follows:
A (0, 5)
B (2, 2)
C (3, 1)
D (4, -1)
The straight line has a constant slope. Therefore it should have the same value when any two of the four points are used to calculate the slope.
Try A and B:
Slope = (2 - 5)/(2 - 0) = -3/2
Try A and C:
Slope = (1 - 5)/(3 - 0) = -4/3
Try A and D.
Slope = (-1 - 5)/(4 - 0) = -3/2
Try B and D.
Slope = (-1 - 2)/(4 - 2) = -3/2
Clearly, C does not lie on the straight line.
Answer: The point that the graph does not pass through is (3,1).
The circle increase in area will be by a factor of 1.5
So corresponding increase in the diameter will be a factor of sqrt 1.5 = 1.2247
Answer is 22.47 %
