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LuckyWell [14K]
3 years ago
12

The daily number of patients visiting a dentist's office during one week are 8, 41, 35, 39, 36, and 42.

Mathematics
2 answers:
umka21 [38]3 years ago
6 0

Answer: The median is the only appropriate measure of center

oksian1 [2.3K]3 years ago
6 0

For those of you who are doin the test rn here are the answers to all of them.

Hope this helps! ;)

I did the quiz

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Find the height of the tree.
Burka [1]

Answer:

16 ft

Step-by-step explanation:

We start by converting 1yd to ft,

1yd = 3ft

So in the smaller triangle, we have 3ft, 4.5ft. Using Sine, Cos, and Tan rule. We know that

TanΦ = opposite / adjacent

TanΦ = 3ft / 4.5ft

TanΦ = 0.667

Φ = Tan^-1 0.6

Φ = 33.69

This means that the angle of elevation is 33.69°

Using this angle, and the same tan rule again, we gave

Tan 33.69 = opp/24

0.667 = opp/24

opp = 24 * 0.667

opp = 16 ft

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3 years ago
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Place parentheses in the expression so that it equals the given value.
vesna_86 [32]
20+2•(5+4^1) keep in mind of PEMDAS, so solve in the order P: Parentheses E: Exponents(in this case you would solve the exponent before the parentheses M: Multiplication D: Division A: Addition S: Subtraction
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3 years ago
Help me please? Thanks!
love history [14]

Answer:

It's C

Step-by-step explanation:


7 0
3 years ago
Will give brainliest !please help <br><br>4b+7b+5​
Alecsey [184]

Answer:

Terms = 4b , 7b , 5

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3 years ago
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Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha
Pavel [41]

Answer:

(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14.

(Expand to obtain an equivalent expression for the sphere: x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0)

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}.

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}.

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between \left(x_1, \, y_1, \, z_1\right) and \left(x_2, \, y_2, \, z_2\right) would be:

\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right).

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}.

The equation for a sphere of radius r and center \left(x_0,\, y_0,\, z_0\right) would be:

\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2.

In this case, the equation would be:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2.

Simplify to obtain:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56.

Expand the squares and simplify to obtain:

x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0.

8 0
3 years ago
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