A car initially contains just its driver. The combined mass of car and driver is 869 kg. When the gas pedal is pushed down all t
1 answer:
Answer:
4.2 m/s²
Explanation:
m = combined mass of car and driver = 869 kg
a = maximum acceleration reached by the car with driver in it = 5.6 m/s²
Force provided by the engine is given as
= ma
= (869) (5.6)
= 4866.4 N
M = Combined mass of car, driver and his three friends = 869 + 300 = 1169 kg
a' = maximum acceleration reached with friends in the car = ?
Force provided by the engine remains same and is then given as
= M a'
4866.4 = (1169) a'
a' = 4.2 m/s²
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Answer:
x = 1474.9 [m]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.
We must understand that when forces are applied on the body, they tend to slow the body down to stop it.
So as the body continues to move to the left, it is slowing down. Therefore we must calculate this deceleration value using Newton's second law. We must perform a sum of forces on the x-axis equal to the product of mass by acceleration. With leftward movement as negative and rightward forces as positive.
ΣF = m*a
Now using the following equation of kinematics, we can calculate the distance of the block, before stopping completely. The initial speed must be 100 [m/s].
where:
Vf = final velocity = 0 (the block stops)
Vo = initial velocity = 100 [m/s]
a = - 3.39 [m/s²]
x = displacement [m]