If a machine has an efficiency of 50 percent and<br> an MA of 3, what is its IMA?

Recessed incandescent luminaires not marked type ic and those marked for installing directly in ___________ must not have insula

slavikrds [6]

Answer:

Recessed incandescent luminaires not marked type ic and those marked for installing directly in insulated ceilings must not have insulation over the top of the luminaire.

Explanation:

Depending on how they interact with insulation, lighting fixtures are rated at various levels. Non-IC rated lighting fixtures can accommodate higher wattage bulbs, but they also pose the greatest fire risk when used with the incorrect insulation.

In locations with insulation, light fixtures that are not IC rated may be installed. But there is a condition. The distance between the fixture and any insulation should be 3 inches. But the 3 inch gap in the insulation would negate the goal of insulation by producing a lot of uninsulated space, so this defies logic. Building a box-style cover to cover the fixture on the attic side is one option to fix this. Drywall or foil-faced foam insulation can be used to create this box. After the cover is put in place, insulation can be added for maximum effectiveness.

To learn more about recessed incandescent luminaries. Click brainly.com/question/17218799

#SPJ4

6 0

2 years ago

I need to know which ones are physical or chemical changes.

andrezito [222]

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Chemical
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I believe this is right but double check to make sure :)

7 0

3 years ago

Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one en

Tom [10]

Explanation:

Wavelength in an emission spectrum, $\lambda=435\ nm=435\times 10^{-9}\ m$

The energy of an electron is given by :

$E=\dfrac{hc}{\lambda}$

Where

h is the Planck's constant

c is the speed of light

For 435 nm, the energy of the electron will be :

$E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8\ m/s}{435\times 10^{-9}}$

$E=4.57\times 10^{-19}\ J$

We know that $1\ eV=1.6\times 10^{-19}\ J$

So, $E=\dfrac{4.57\times 10^{-19}}{1.6\times 10^{-19}}$

So, E = 2.86 eV

The energy of the electron dropping from one energy level is 2.86 eV. We know that,

$\dfrac{hc}{\lambda}=E_{n_2}-E_{n_1}$

From the given energy levels :

$E_5-E_2=-0.544-(-3.403)$

$E_5-E_2=2.859\ eV$

So, the transition must be from E₅ to E₂. Hence, this is the required solution.

5 0

4 years ago

Read 2 more answers

A car is traveling at a constant speed of 12m/s , when the driver accelerates the car reaches a speed of 26 m/s in 6s what is th

DaniilM [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed)

Change in speed = (26 m/s) - (12 m/s) = 14 m/s

Time for the change = 6 s

Acceleration = (14 m/s) / (6 s)

Acceleration = (14/6) (m/s²)

<em>Acceleration = 2.33 m/s²</em>

7 0

4 years ago

Stars which never disappear below the horizon are called__stars. A. Polaris B. visible C. constellation D. circumpolar

miss Akunina [59]

Answer:

D. circumpolar

Explanation:

A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.

-Wikipedia

5 0

4 years ago

If a machine has an efficiency of 50 percent and an MA of 3, what is its IMA?