Answer:
20
Step-by-step explanation:
Two tangent segments drawn to a circle from the same point outside the circle are congruent. The two tangents at A measure 2. The two tangents at B measure 5. The two tangents at C measure 3.
perimeter = 2 + 2 + 5 + 5 + 3 + 3
perimeter = 20
Answer:
The correct answer is C if the answers are the same as the picture attached.
since T is the midpoint of SU, then ST = TU.
![\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B10x-14%7D%7B%5Cboxed%7BS%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20T%5Cstackrel%7B5x%2B16%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BU%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10x-14%7D%3D%5Cstackrel%7BTU%7D%7B5x%2B16%7D%5Cimplies%205x-14%3D16%5Cimplies%205x%3D30%5Cimplies%20x%3D%5Ccfrac%7B30%7D%7B5%7D%5Cimplies%20x%3D6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10%286%29-14%5Cimplies%2046%7D~%5Chfill%20%5Cstackrel%7BTU%7D%7BTU%3DST%3D46%7D~%5Chfill%20%5Cstackrel%7BSU%7D%7BST%2BTU%3D92%7D)
Answer:
x = 55
y = 45
Step-by-step explanation:
In similar triangles, the ratio between similar sides are the same. So,
AB/ED = BC/EF = AC/DF
Substitute values that they give
6/15 = 18/y = 22/x
Solve 6/15 = 18/y by cross-multiplying
6y = 15*18 = 324
Divide both sides by 6
y= 45
Solve 6/15 = 22/x by cross-multiplying.
6x = 22*15 = 330
Divide both sides by 6.
x = 55
Because there is some dispute between the answers, let's check the ratios.
6/15 = 18/45 = 22/55
0.4 = 0.4 = 0.4
True, x = 55 and y=45
