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3 years ago

The phrase "six less than twice y" can be represented by the algebraic expression.

Mathematics

2 answers:

cluponka [151]3 years ago

6 0

Answer:

six less than twice y is represented by 2y - 6

Naily [24]3 years ago

6 0

The answer is 2y-6 because it’s insinuating that you are taking away 6 from the variable.

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CONSTRUCTED RESPONSE

Digiron [165]

The fraction for the above ratio is 5/9

Where 5- no of cups of bread crumbs needed; 9= pounds of ground beef needed

Step-by-step explanation:

Anything that can be represented in the x/y form constitutes the fraction.

The above statement can be represented in the fraction form as 5/9. It means that for every 9 pounds of ground beef, 5 cups of bread crumbs are needed.

The above fraction provides the ratio in the form of cups of bread crumb/ pound of ground beef required. Where 5 represents the number of cups of bread crumbs required, 9 represents the pound of ground beef needed for the same.

3 0

3 years ago

wind turbines generate large amounts of electricity from wind energy. the blades on a wind turbine can revolve 22 times per minu

lesya [120]

Answer:

1320 times

Step-by-step explanation:

Time = 1 h × (60 min/1 h) = 60 min

Revolutions = 60 min × (22 rev/1 min) = 1320 rev

The blades revolve 1320 times per hour.

5 0

3 years ago

Find , , and if and terminates in quadrant .

ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

• cos2x

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

$\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}$ $\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}$

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

$\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})$ $=\frac{12}{13}$

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

$\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}$

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

$\tan 2x=\frac{2\tan x}{1-\tan ^2x}$ $=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}$ $=\frac{\frac{4}{3}}{1-\frac{4}{9}}$ $=\frac{\frac{4}{3}}{\frac{9-4}{9}}$ $=\frac{\frac{4}{3}}{\frac{5}{9}}$ $=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}$