Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
Answer:
One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
Step-by-step explanation:
B and E are the correct answers, as 2/100 is the same thing as 0.02.
Answer:
see explanation
Step-by-step explanation:
Given the 3 equations
3x + 5y + 5z = 1 → (1)
x - 2y = 5 → (2)
2x + 4y = 11 → (3)
Use (2) and (3) to solve for x and y
Multiply (2) by 2
2x - 4y = 10 → (4)
Add (3) and (4) term by term
4x = 21 ( divide both sides by 4 )
x = 
Substitute this value of x into (3)
2 × + 4y = 11
+ 4y = 11 ( subtract from both sides )
4y = 
( divide both sides by 4 )
y = 
Substitute the values of x and y into (1) and solve for z
3 × + 5 × + 5z = 1
+ 
+ 5z = 1
+ 5z = 1 ( subtract from both sides )
5z = - 
( divide both sides by 5 )
z = - 
Solution is
x = , y = , z = -
Answer:
a) 122.5 m ; b) 10 s
Step-by-step explanation:
Just use the given equation and plug in what you know.
a)
d = 4.9t^2
d = 4.9(5^2)
d = 4.9 * 25
d = 122.5 m
b)
d = 4.9t^2
490 = 4.9t^2
100 = t^2
t = 10 s
