Answer:
(3,0) the graph touches the x-axis
Step-by-step explanation:
the graph of ![y = (x + 2)(x + 1)(x – 3)^2](https://tex.z-dn.net/?f=y%20%3D%20%28x%20%2B%202%29%28x%20%2B%201%29%28x%20%E2%80%93%203%29%5E2)
we need to check what happens to the graph near the point (3,0)
In f(x) we have (x-3)^2
LEts plug in 3 for x and check
![y = (3 + 2)(3 + 1)(3 – 3)^2](https://tex.z-dn.net/?f=y%20%3D%20%283%20%2B%202%29%283%20%2B%201%29%283%20%E2%80%93%203%29%5E2)
y=0, so (3,0) is one of the zero of the given f(x)
In f(x) we have ![(x-3)^2](https://tex.z-dn.net/?f=%28x-3%29%5E2)
Exponent is 2 that is even. It means the multiplicity is even.
When the multiplicity is even then the graph touches the x axis but does not cross x axis
So at (3,0) the graph touches the x-axis
9514 1404 393
Answer:
a. 5^-3
b. 14^18
c. 8^9
d. 16^3
e. 21^-18
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
(a^b)^c = a^(bc)
__
a) 5^(3-6) = 5^-3
b) 14^(3·6) = 14^18
c) 8^(3+6) = 8^9
d) 16^(6-3) = 16^3
e) 21^(3(-6)) = 21^-18
You would need 6 packages for 27 students because 27 isn't divisible by 5 without a remainder and all students need pencils. So, you would need to bu another package of pencils.
Given is the base area of a solid crate, B = 6 square meters.
Given is the height of the solid crate, H = 4 meters.
We know the formula for volume of any solid is given as follows :-
(Volume of the solid) = (Base area of the solid) x (Height of the solid).
Volume = B x H.
Volume = (6 square meters) x (4 meters).
Volume = 24 cubic meters.
Hence, the volume of the solid crate would be 24 cubic meters.
Answer:
when you simplify you continue until you get to the simplest form but when you solve you continue until you get an answer. Solving gives you a value for a variable. You mean simplify and get 2x - 10 but when you solve you continue until you get x as 5
Step-by-step explanation: