How do you evaluate: To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.
Answer:
Part A : y²(x + 2)(x + 4)
Part B: (x + 4) (x + 4)
Part C: (x + 4) (x - 4)
Step-by-step explanation:
Part A: Factor x²y²+ 6xy²+ 8y²
x²y²+ 6xy²+ 8y²
y² is very common across the quadratic equation , hence
= y² (x² + 6x + 8)
= (y²) (x² + 6x + 8)
= (y²) (x² + 2x +4x + 8)
= (y²) (x² + 2x)+(4x + 8)
= (y²) (x(x + 2)+ 4(x + 2))
= y²(x+2)(x+4)
Part B: Factor x² + 8x + 16
x² + 8x + 16
= x² + 4x + 4x + 16
= (x² + 4x) + (4x + 16)
= x( x + 4) + 4(x + 4)
= (x + 4) (x + 4)
Part C: Factor x² − 16
= x² − 16
= x² + 0x − 16
= x² + 4x - 4x - 16
= (x² + 4x) - (4x - 16)
= x (x + 4) - 4(x + 4)
= (x + 4) (x - 4)
Work backwards with pythagoras' theorem:
c^2=a^2+b^2
Here, a and b both equal to x. Therefore, you can write this as 8^2=2x^2. So 64=2x^2. Sqrt on both sides to give you 8=2x, hence x=4. However I must warn you that this working out may have a flaw, as I found that x actually equals to 5.66
The probability of rolling a 2 is 1/6. If X is a random variable representing the number of 2s that are obtained after rolling a die 23 times, then X follows a binomial distribution with success probability p = 1/6 across n = 23 trials.
The variance of a binomial distribution with parameters p and n is n p (1 - p), so the standard deviation in this case would be
√(23 • 1/6 • 5/6) ≈ 1.8
A. none it is oveer 180 and a triangle must equal 180 degrees
