Answer:
<em>H₀</em>: The voting preference of men and women are not different.
<em>Hₐ</em>: The voting preference of men and women are not different.
Step-by-step explanation:
A hypothesis test for two proportions can be used to determine whether the preference of men differ from women in case of voting.
A Chi-square test contingency table can be used to perform the test.
The hypothesis can be defined as:
<em>H₀</em>: The voting preference of men and women are not different.
<em>Hₐ</em>: The voting preference of men and women are not different.
The test statistic is:
Decision rule:
If the <em>p</em>-value of the Chi-square test statistic is less than the significance level <em>α</em> = 0.05 then the null hypothesis will be rejected. And if the <em>p</em>-value is more than the significance level then the null hypothesis will not be rejected.
<span>To solve this problem, we can use this formula d = rd (distance = rates x time)
She runs at a speed of 9 mph and walks at a speed of 3 mph.
Her distance running is
d = 9tr
where tr is the time she spends running
Her distance walking is
d = 3tw
where tw is the time she spends walking
The distances are the same so
9tr = 3tw
We also know that the total time is 5 hours
tr + tw = 5
tr = 5-tw
Substitute this value of tr in the first equation
9tr = 3tw
9(5-tw) = 3tw
45-9tw = 3tw
45 = 12tw
3.75= tw
Denise will spend 3.75 hours (3 hours, 45 minutes) walking back and 1.25 hours (1 hour, 15 minutes) running.</span>
Let be:Speed of the wind: WSpeed of the plane in still air: P
Against the wind the plane flew:Distance: d=175 milesTime: ta=1 hour 10 minutesta=1 hour (10 minutes)*(1 hour/60 minutes)ta=1 hour + 1/6 hourta=(6+1)/6 hourta=7/6 hourSpeed against the wind: Sa=d/taSa=(175 miles) / (7/6 hour)Sa=175*(6/7) miles/hourSa=1,050/7 miles per hourSa=150 mph
(1) P-W=Sa(1) P-W=150
The return trip only took 50 minutesDistance: d=175 milesTime: tr=50 minutestr=(50 minutes)*(1 hour/60 minutes)tr=5/6 hour
Speed retur trip: Sr=d/trSr=(175 miles) / (5/6 hour)Sr=175*(6/5) miles/hourSr=1,050/5 miles per hourSr=210 mph
(2) P+W=Sr(2) P+W=210
We have a system of 2 equations and 2 unknows:(1) P-W=150(2) P+W=210
Adding the equations:P-W+P+W=150+2102P=360Solving for P:2P/2=360/2P=180
Replacing P by 180 in equation (2):(2) P+W=210180+W=210
Solving for W:180+W-180=210-180W=30
Answers:The speed of the plane in still air was 180 mphThe speed of the wind was 30 mph
Answer:
It's B. 0.4
Step-by-step explanation:
the first probability is 0.6 and 0.6+x=1 so x is 0.4
