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Harman [31]
3 years ago
15

00:00

Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

B. 16 and 56

Step-by-step explanation:

The greatest common factor or GCF, is the highest whole number that is a factor, or that multiplies to get, two or more numbers.

For example, option a, 8 and 28. 8 is a factor of 8, 8 times 1, but 8 is not a factor of 28. 28 divided by 8 will not give you a whole number.

Option c, 32 and 16, both have factors of 8. 4*8 is 32 and 8*2 is 16. This however, is not the gcf, because the true gcf is 16. 16*1 is 16 and 16*2 is 32. 16 will go into both evenly and is the highest number that will do so and is the gcf of that pair

d, 40 and 55, is the same as the first. 8*5 is 40, but 8 will not evenly go into 55 and cannot be a factor.

That leaves you with 16 and 56, the correct option

16 only has 3 factors, 16*1, 8*2, and 4*4, so 16, 8 and 4.

56 has more factors, 28, 14, 8, 7, 4, and 2. Those are the only numbers that multiply together to get 56. The highest number in both those lists is 8, so 8 is the Greatest Common Factor.

Hope this helps, and brainliest is much appreciated! Have an awesome day.

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Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

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Learn more about integration at brainly.com/question/27419605

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