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Harman [31]
3 years ago
15

00:00

Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

B. 16 and 56

Step-by-step explanation:

The greatest common factor or GCF, is the highest whole number that is a factor, or that multiplies to get, two or more numbers.

For example, option a, 8 and 28. 8 is a factor of 8, 8 times 1, but 8 is not a factor of 28. 28 divided by 8 will not give you a whole number.

Option c, 32 and 16, both have factors of 8. 4*8 is 32 and 8*2 is 16. This however, is not the gcf, because the true gcf is 16. 16*1 is 16 and 16*2 is 32. 16 will go into both evenly and is the highest number that will do so and is the gcf of that pair

d, 40 and 55, is the same as the first. 8*5 is 40, but 8 will not evenly go into 55 and cannot be a factor.

That leaves you with 16 and 56, the correct option

16 only has 3 factors, 16*1, 8*2, and 4*4, so 16, 8 and 4.

56 has more factors, 28, 14, 8, 7, 4, and 2. Those are the only numbers that multiply together to get 56. The highest number in both those lists is 8, so 8 is the Greatest Common Factor.

Hope this helps, and brainliest is much appreciated! Have an awesome day.

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Step-by-step explanation:

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The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
tatuchka [14]

Answer:

a)Null hypothesis:- H₀: μ> 500

  Alternative hypothesis:-H₁ : μ< 500

b) (5211.05 , 5411.7)

95% lower confidence bound on the mean.

c) The test of hypothesis t = 5.826 >1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

Step-by-step explanation:

<u>Step :-1</u>

Given  a random sample of 15 devices is selected in the laboratory.

size of the small sample 'n' = 15

An average life of 5311.4 hours and a sample standard deviation of 220.7 hours.

Average of sample mean (x⁻) =  5311.4 hours

sample standard deviation (S) = 220.7 hours.

<u>Step :- 2</u>

<u>a) Null hypothesis</u>:- H₀: μ> 500

<u>Alternative hypothesis</u>:-H₁ : μ< 500

<u>Level of significance</u> :- α = 0.95 or 0.05

b) The test statistic

t = \frac{x^{-} - mean}{\frac{S}{\sqrt{n-1} } }

t = \frac{5311.4 - 500}{\frac{220.7}{\sqrt{15-1} } }

t = 5.826

The degrees of freedom γ= n-1 = 15-1 =14

tabulated value t =1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

calculated value t = 5.826 >1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

Null hypothesis is rejected at  95% confidence on the mean.

C) <u>The 95% of confidence limits </u>

(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-} + t_{0.05}\frac{S}{\sqrt{n} } )

substitute values and simplification , we get

(5311.4 - 1.761 \frac{220.7}{\sqrt{15} } ,5311.4 +1.761\frac{220.7}{\sqrt{15} } )

(5211.05 , 5411.7)

95% lower confidence bound on the mean.

5 0
3 years ago
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sp2606 [1]

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Step-by-step explanation:

The slope can be calculated with the following formula:

m=\frac{y_2-y_1}{x_2-x_1}

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m=\frac{-1-1}{-1-2}\\\\m=\frac{-2}{-3}\\\\m=\frac{2}{3}

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Step-by-step explanation:

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Answer:

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