Answer:
(y+2)=2(x−3)
Or
(y−4)=2(x-6)
Or
y=2x−8
Step-by-step explanation:
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:
Step-by-step explanation:
i Believe its A. B. And D. But i could be wrong
Given AP is 21 ,18,15,...
First term = 21
Common difference = 18-21 = -3
Let an = -81
We know that
an = a+(n-1)d
⇛21+(n-1)(-3) = -81
⇛ 21-3n+3 = -81
⇛24-3n = -81
⇛ 24+81 = 3n
⇛ 105= 3n
⇛ n = 105/3
⇛ n = 35
35th term of the AP is -81.
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Assuming Mark wants to buy a PS5 for $499.00 and the tax in her local county is 7.75% of the total sale, what will be the final cost is $538
Using this formula
Final cost =Total sales+ (Total sales×Tax)
Let plug in the formula
Final cost= $499.00+($499.00×7.75%)
Final cost= $499.00+$38.67
Final cost= $537.67
Final cost= $538 (Approximately)
Inconclusion Assuming Mark wants to buy a PS5 for $499.00 and the tax in her local county is 7.75% of the total sale, what will be the final cost is $538
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