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3 years ago

Which polygon has an interior angle sum of 1080

2 answers:

6 0

The sum of the interior angles in a regular polygon is given by the formula 180(n – 2), where n is the number of sides in the polygon. An octagon has eight sides, so the sum of the angles of the octagon is 180(8 – 2) = 180(6) = 1080 degrees. In other word your answer would be an octagon.

larisa [96]3 years ago

5 0

Answer:

The correct one is A one with 8 points

Step-by-step explanation:

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Help on test pls! asap!!

Tanzania [10]

Answer:

1) D it doesn't pass the line test

2)B

3)A C F

4 0

3 years ago

What is the area of this polygon?

elena55 [62]

A= 192 cm squared
Why?
17 x 10= 170
4 x 11= 44
44 divided by 2 =22
170+ 22= 192 cm squared

3 0

2 years ago

Read 2 more answers

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

3 years ago

Find the domain of the function (f/g)(x) where f(x)=√x+1, g(x)=√x-9

nadya68 [22]

Answer:

4x + 9. Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x). (g o g)(x) = g(g(x)) ... Given f (x) = sqrt(x) and g(x) = x – 2, find the domains of ( f o g)(x) and (g o f )(x). Since f (x) involves a square root, the inputs have to be non-negative. ... Given h(x) = (x + 1)2 + 2(x + 1) – 3, determine two functions f (x) and g(x

Step-by-step explanation:

4 0

3 years ago

Is this right ? Im honestly confused

fgiga [73]

Answer:

In step by step

Step-by-step explanation:

For #1, everything is perfect.

For #2, you wrote your functions out incorrectly, but your x input and y output are correct

#3 is a little messed up.

Your function is f(x)=-3x+1. Your given x's are -3, -1, 0, 1, 2, and 3. Plug all of these in.

1. f(-3)=-3(-3)+1

f(-3)=9+1
f(-3)=1

2. f(-1)=-3(-1)+1

f(-1)=3+1
f(-1)=4

3. f(0)=-3(0)+1

f(0)=0+1
f(0)=1

4. f(1)=-3(1)+1

f(1)=-3+1
f(1)=-3

5. f(2)=-3(2)+1

f(2)=-6+1
f(2)=-5

3 0

3 years ago