When you foil it out you should get: 2x^5-2x^3-12x. When you factor it out completely you get: 2x(x^2-3)(x^2+2)
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
Answer:
(x , y) = (-2 , 1)
Step-by-step explanation:
multiply both sides by -1
sum the equations vertically to eliminate at least one variable
divide both sides by -8
substitute the value of y into the equation
now solve for x using that y=1
Answer:
3558 people
Step-by-step explanation:
Since the attendance dropped 8 percent, we know that it's currently at 92% of the original number. We can set up proportions to help us solve this
92/100=3274/x
From here, we can multiply both sides by 100
3274x100 is 327400
Then we multiply both sides by x
Now we are left with 92x=327400
Divide both sides by 92
327400/92 = 3558.7
Obviously we can't have .7 of a person so I would round it down to 3558 people
Answer:
P(X > 5) = 0.1164 to 4 d.p.
The parameters are defined in the explanation.
Step-by-step explanation:
This is a binomial distribution problem
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of potential hires = 10
x = Number of successes required = number of potential hires that have prior call centre experience = more than half; that is, x > 5
p = probability of success = probability that any potential hire will have experience = (11/30) = 0.367
q = probability of failure = probability that any potential hire will NOT have experience = 1 - p = 1 - 0.367 = 0.633
P(X > 5) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)
Inserting the parameters and computing the probabilities for each of those values of X,
P(X > 5) = 0.11641775484 = 0.1164 to 4 d.p.
Hope this Helps!!!