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vaieri [72.5K]
3 years ago
5

What is the range of the following relation?{(5,0), (6, -1), (1, 4), (0,5), (2,3)}​

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

ANSWER

The range is

{-1,0,1,3,4,5}

EXPLANATION

The relation is given to us as an ordered pair.

The range is the set of all the y-values of the relation.

We list the set of all the values in ascending order without any repetition.

We then obtain the range as:

{-1,0,1,3,4,5}

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What is the value of the expression?
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Step-by-step explanation:

1 Simplify  \sqrt{8}

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  to  2\sqrt{2}2

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​

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\frac{2}{6\times 2\sqrt{2}}\sqrt{2}-(-\frac{18}{\sqrt{81}})

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  to  12\sqrt{2}12

2

​

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\frac{2}{12\sqrt{2}}\sqrt{2}-(-\frac{18}{\sqrt{81}})

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−(−

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3 Since 9\times 9=819×9=81, the square root of 8181 is 99.

\frac{2}{12\sqrt{2}}\sqrt{2}-(-\frac{18}{9})

12

2

​

2

​

 

2

​

−(−

9

18

​

)

4 Simplify  \frac{18}{9}

9

18

​

  to  22.

\frac{2}{12\sqrt{2}}\sqrt{2}-(-2)

12

2

​

2

​

 

2

​

−(−2)

5 Rationalize the denominator: \frac{2}{12\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{2\sqrt{2}}{12\times 2}

12

2

​

2

​

⋅

2

​

2

​

​

=

12×2

2

2

​

​

.

\frac{2\sqrt{2}}{12\times 2}\sqrt{2}-(-2)

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​

​

 

2

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−(−2)

6 Simplify  12\times 212×2  to  2424.

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​

 

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−(−2)

7 Simplify  \frac{2\sqrt{2}}{24}

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​

​

  to  \frac{\sqrt{2}}{12}

12

2

​

​

.

\frac{\sqrt{2}}{12}\sqrt{2}-(-2)

12

2

​

​

 

2

​

−(−2)

8 Use this rule: \frac{a}{b} \times c=\frac{ac}{b}

b

a

​

×c=

b

ac

​

.

\frac{\sqrt{2}\sqrt{2}}{12}-(-2)

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2

​

 

2

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​

−(−2)

9 Simplify  \sqrt{2}\sqrt{2}

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​

 

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​

  to  \sqrt{4}

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​

.

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​

−(−2)

10 Since 2\times 2=42×2=4, the square root of 44 is 22.

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11 Simplify  \frac{2}{12}

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  to  \frac{1}{6}

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1

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−(−2)

12 Remove parentheses.

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+2

13 Simplify.

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13

​

Done

4 0
1 year ago
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