What is the range of the following relation?{(5,0), (6, -1), (1, 4), (0,5), (2,3)}

Mathematics

1 answer:

murzikaleks [220]3 years ago

8 0

ANSWER

The range is

{-1,0,1,3,4,5}

EXPLANATION

The relation is given to us as an ordered pair.

The range is the set of all the y-values of the relation.

We list the set of all the values in ascending order without any repetition.

We then obtain the range as:

{-1,0,1,3,4,5}

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a. What is the area and circumference of circle P? Explain how you calculated this answer. b. If the arc measure of arc COD is 1

Vikki [24]

Answer:

a) 9*π or approx 28.26

b) ∡CRB=100°

Step-by-step explanation:

As known for secants crossing each other inside the circle is coorect the following:

BR*RD=AR*RC

=> 3*RD=4*4.5

RD=6

The diameter of the circle with center P is BD=BR+RD=3+6=9

So the radius of the circle is D/2=9/2=4.5

As known the circumference of any circle can be calculated as

C=2*π*r , where r is the circle's radius

So C=2*4.5*π=9*π= approx 3.14*9=28.26

b) ∡CRB=∡ARD= (arcBC+arcAD), where arcBC and arcAD smaller arcs

BD is the circle's diameter, so arc BD=180°

So arcBC=180°-arcCOD=180°-100°=80°

Similarly arcBD=180°

arcAD=180°-arcBSA=180°-60°=120°

∡CRB= (80°+120°)/2=100°

5 0

3 years ago

Write an equation in point-slope form, y – y1 = m(x – x1), of the line through points (9, –2) and (10, 2). Use (9, –2) as the po

True [87]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& -2~) 
% (c,d)
&&(~ 10 &,& 2~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{10-9}\implies \cfrac{2+2}{10-9}\implies \cfrac{4}{1}\implies 4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=4(x-9)\implies y+2=4(x-9)$