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enot [183]
3 years ago
14

3 to the power of -3 times 10 to the power of -3

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

0.00003703703

Step-by-step explanation:

(3 to the power (-3))*(10 to the power (-3))

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Solve the simultaneous equations
puteri [66]

Answer:

The answer is in the pictures.

Step-by-step explanation:

5 0
1 year ago
If the orientation of two shapes is not the same, which transformation(s) should you use to show they are congruent? Why?
Aleksandr-060686 [28]

Answer:

The answer is below

Step-by-step explanation:

Transformation s the movement of a point from its initial location to a new location. If an object is transformed, the all its points are also transformed. Types of transformation are rotation, reflection, translation and dilation.

Two shapes are congruet if they have the same shape and size, two objects are congruent if they can be moved without changing their shape or size. Congruent transformations are transformation that create congruent objects. The three types are:

  1. Translation: sliding an object either up, down, left or right.
  2. Reflection: Flipping an object over a line
  3. Rotation: turning an object about a point
4 0
3 years ago
Read 2 more answers
Match the right side of the equation to the left side<br> cot x sec^4 x=cot x+ 2 tan x+tan^3 x
Natalka [10]

Step-by-step explanation:

cot x + 2 tan x + tan³ x

Write in terms of sine and cosine:

(cos x / sin x) + 2 (sin x / cos x) + (sin³ x / cos³ x)

Find the common denominator:

(cos⁴ x / (sin x cos³ x) + 2 (sin² x cos² x / (sin x cos³ x)) + (sin⁴ x / (sin x cos³ x))

Add:

(cos⁴ x + 2 sin² x cos² x + sin⁴ x) / (sin x cos³ x)

Factor:

(sin² x + cos² x)² / (sin x cos³ x)

Pythagorean identity:

1 / (sin x cos³ x)

Multiply top and bottom by cos x:

cos x / (sin x cos⁴ x)

Simplify:

cot x sec⁴ x

5 0
3 years ago
can someone please help? And can you also explain how to do it, because I forgot the steps on how to do it ​
alexdok [17]

Answer:

option 3) EF= -7 FG= -7

Step-by-step explanation

X= 1/2

EF= 2X-8

    = 2 X 1/2 -8

    =1 - 8

EF = -7

FG= 4X -9

     = 4X 1/2

     2 - 9

FG     = -7

7 0
3 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2&#10;\\\\\\\&#10;[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]&#10;\\\\\\&#10;2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)&#10;\\\\\\&#10;\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}&#10;\\\\\\&#10;\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}&#10;\\\\\\&#10;\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}&#10;\\\\\\&#10;\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
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