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Ganezh [65]
3 years ago
13

What is 4x+60=100? Solve for x.

Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0

Step-by-step explanation:

collect like terms

4x = 100 - 60

4x = 40

X = 40//4= 10

-BARSIC- [3]3 years ago
3 0

Answer:  The answer is x=10

You might be interested in
What two numbers multiply to 120 and add to -26
Arisa [49]
The two numbers are -6 and -20

-20 x -6 = 120

-20 + (-6) = -26


3 0
3 years ago
the diagram shows a 5cm x 5cm x 5cm cube calculate the length of the diagonal AB give your answer correct to 1 decimal place
Lynna [10]

Answer:

√3 * 5 = 5√3 cm

Step-by-step explanation:

→ ABCDEFGH is a cube.

→ CF = Diagonal of cube.

→ CH = Diagonal of Base Face BCDH.

→ Let the side of Each cube = a.

Than,

in Right ∆CFH, By Pythagoras Theoram, we have,

→ CH² + FH² = CF² --------- Equation (1)

and, Similarly, in Right ∆CDH ,

→ CD² + DH² = CH² ------- Equation (2).

Putting Value of Equation (2) in Equation (1), we get,

→ (CD² + DH²) + FH² = CF²

→ a² + a² + a² = CF²

→ CF² = 3a²

→ CF = √3a .

Hence, we can say That Diagonal of a cube is √3 times of its sides.

__________________

Given:-

Side of cube = 5cm.

So,

→ Diagonal of cube = √3 * 5 = 5√3 cm. (Ans.)

4 0
3 years ago
Which is the choice to the inequality below?
Nuetrik [128]

Answer:

x < -36

Step-by-step explanation:

-x/9>4

Multiply each side by -9, remembering to flip the inequality

-x/9 * -9 < 4*-9

x < -36

5 0
4 years ago
The ratio of the length of a rectangle is 5:2, express the difference between the length and the width of the rectangle as a fra
Otrada [13]
5-2 to find the difference and then its (difference/length) so, (3/5) is the answer. Hope it helped!
6 0
3 years ago
Read 2 more answers
A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
Jet001 [13]
A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
  3 W + 2 M OR (we have found it in c) = 2,520)
  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
  5 W + 0 M OR   ⁸C₅ x ¹⁰C₀   →→→→  =     56

Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
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