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aev [14]
3 years ago
13

Consider that ΔABC is similar to ΔXYZ and the measure of ∠B is 68°. What is the measure of ∠Y?

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0

Answer:

68°

Corresponding angles of similar figures are congruent.

olga nikolaevna [1]3 years ago
5 0

Answer:

\angle y=68 \textdegree

Step-by-step explanation:

Similar triangle:

In\ a\ similar\ triangle\ corresponding\ angles\ are\ equal\\\\\angle X=\angle A\\\\\angle Y=\angle B\\\\\angle Z=\angle C\\\\Then\ \angle Y=68 \textdegree

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Solve 8m-2(14-m)>7(m-4)+3m
emmasim [6.3K]

Answer:

0>0 or error

Step-by-step explanation:

8m-2(14-m)>7(m-4)+3m

8m-28+2m>7m-28+3m

10m-28>10m-28

0>0

5 0
2 years ago
The points (-2 11) and (6 3) lie on the same line. What is the x-intercept of the line.
ololo11 [35]
The x-intercept is (11.43,0) I don’t know how to explain it to you
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3 years ago
Find the exact solutions of the problem algebraically: tan 2x-cot x=0
Eva8 [605]
Tan 2x - cot x = 0
2tan x / (1 - tan^2 x) - 1/tan x = 0
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5 0
3 years ago
One employee pours 6 ounces of coffee in the large frappuccino.
Reil [10]

Answer:

The employee's action <u>is not following the instructions</u>.

Step-by-step explanation:

The drinks table has some recommendations to make some drinks exclusive to the establishment such as the Large Frapuccino or the Small Chai Tea, which in its first line corresponding to the Large Frapuccino specifies that at least 8 ounces of coffee should be used, which it wants to say is the <u>minimum amount of coffee that can be added to it is 8 ounces</u>, and the value could be higher than that, but never lower, which is why by adding only 6 ounces to the Frapuccino you are totally ignoring the instructions.

8 0
3 years ago
McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
3 years ago
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