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marysya [2.9K]
3 years ago
14

What values make the inequality x+6/6-x true?

Mathematics
2 answers:
lianna [129]3 years ago
8 0

Here it is guys for you guys who is taking the quiz on edugenity who’s testing

kifflom [539]3 years ago
6 0
The correct question is
<span>What values make the inequality (x+6)/(6-x)<0 true?

we know that
</span>
<span>the denominator cannot be zero;
so
(6-x)------------> will be  0 if  x=6

the inequality is true
when
(x+6) > 0  and (6-x) < 0--------> case 1
or
</span>(x+6) < 0  and (6-x) > 0--------> case 2
<span>
case 1
</span>(x+6) > 0  and (6-x) < 0
(x+6) > 0  --------------> x> -6
(6-x) < 0 ----------------> x>  6
 solution--------> (6,∞)

case 2
(x+6) < 0  and (6-x) > 0
(x+6) < 0  --------------> x< -6
(6-x) > 0 ----------------> x < 6
 solution--------> (-∞,-6)
 
the answer is
the values that makes  the inequality true are
(-∞,-6) ∩ (6,∞)

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yanalaym [24]

First we have to understand what the domain is. In a nutshell the domain is the set of all x values that are represented in any given graph. In this case we do not have a graph but we have the vertex. The x value is 2, therefore: x ≥ 2.


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4 years ago
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5 0
3 years ago
Need help with this
sashaice [31]

Answer:

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Step-by-step explanation:

So to create equal fractions, you must multiply both the denominator and numerator by the same number.

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\frac{1}{2} *\frac{3}{3} =\frac{3}{6} =\frac{1}{2}

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5 0
3 years ago
In the figure given below CP=x+3, PA=3x+19, CQ=x and QB=3x+4 then, what value of x will make PQ || AB?
zhenek [66]

Given that

PQ || AB

CP = x+3

PA = 3x+19

DC = x+3

CA = x

QB = 3x+4

We know that

By Basic Proportionality Theorem,

CP / PA = CQ / QB

On substituting these values in the above formula

⇛ (3x+19) / (x+3) = (3x+4) / x

On applying cross multiplication then

⇛ x(3x+19) = (3x+4)(x+3)

⇛ 3x²+19x = 3x(x+3)+4(x+3)

⇛ 3x²+19x = 3x²+9x+4x+12

⇛ 3x²+19x = 3x²+13x+12

⇛ 3x²+19x-3x²-13x = 12

⇛ (3x²-3x²)+(19x-13x) = 12

⇛ 0+6x = 12

⇛ 6x = 12

⇛ x = 12/6

⇛ x = 2

∴ , x = 2

<u>Answer:</u> The value of x for the given problem is 2

<em>Additional</em><em> comment</em><em>:</em>

<u>Basic Proportionality Theorem</u>

" A line drawn parallel to the one side of a triangle intersecting other two sides at two different points, then the line divides the other two sides in the same ratio".

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6 0
2 years ago
Is 7/8 or 11/10 closer to 1? how did you decide?
nirvana33 [79]
11/10 is closer to 1. 
To solve for this, give them common denominators. Lets make it 80 for this one.
To get 80, you multiply 8 by 10, so you have to do the same to the number on top. This gives you 70/80.
To get 80 for the second fraction, you multiply by 8 and get 88/80.
Now lets take the numbers on top and subtract them from 80. 
88 - 80 = 8
80 - 70 = 10
8 is less than 10, and so 11/10 is closer.
7 0
3 years ago
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