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VikaD [51]
2 years ago
10

Evaluate the following expressions given x=6 and y=-3

Mathematics
1 answer:
Nana76 [90]2 years ago
7 0

a.

\purple{5 \times 6 - 4 \times ( - 3)}

= 30 + 12

\blue{ =  \boxed{42}}

b.

\purple{ {6}^{2}  +  \frac{6}{ - 3} }

= 36 - 2

\blue{ =  \boxed{34}}

c.

\purple{(6 - 5 {)}^{3}  +  {( - 3)}^{2} }

=  {1}^{3} + 9

= 1 + 9

\blue{ =  \boxed{10}}

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
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write the equation in slope intercept form of the line that passes through -1, 11 and is parallel to the graph of y = -8x + 3
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<h2>Answer: The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ). </h2>

<h3 /><h3>Step-by-step explanation: </h3>

<u>Find the slope of the parallel line</u>

When two lines are parallel, they have the same slope.

                 ⇒  if the slope of this line = - 8

                      then the slope of the parallel line (m) = - 8

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:  

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                                ∴  y - 11  = - 8 (x + 1)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                      since   y - 11  = - 8 (x + 1)

                                        y  = - 8 x  + 3

The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ).

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