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VikaD [51]
3 years ago
10

Evaluate the following expressions given x=6 and y=-3

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0

a.

\purple{5 \times 6 - 4 \times ( - 3)}

= 30 + 12

\blue{ =  \boxed{42}}

b.

\purple{ {6}^{2}  +  \frac{6}{ - 3} }

= 36 - 2

\blue{ =  \boxed{34}}

c.

\purple{(6 - 5 {)}^{3}  +  {( - 3)}^{2} }

=  {1}^{3} + 9

= 1 + 9

\blue{ =  \boxed{10}}

<h2>=============================</h2>

Hope it helps

<h2>=============================</h2>
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Sketch the sinusoidal function that passes through (0,-6) , has a period of 12 and an amplitude of 3
riadik2000 [5.3K]

The sinusoidal function that passes through (0,-6), has a period of 12 and an amplitude of 3 will be y = 3 sin 12x - 6.

What is a sinusoidal Function?

It is a function that repeats itself in a particular time interval.

The equation is given as

y = Asin (ωx + Ф) + k

We have

Amplitude (A) = 3

Period (ω) = 12

Phase difference (Ф) = 0

Then the equation will be

y = 3 sin 12x + k

The function is passing through (0, -6). Then we have

-6 = 3sin (12 × 0) + k

-6 = k

Then the equation will be

y = 3 sin 12x - 6

More about the sine function link is given below.

brainly.com/question/3876065

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4 0
2 years ago
Y = 6x + 11<br> 2х - Зу = 7
irakobra [83]

9514 1404 393

Answer:

  (x, y) = (-2.5, -4)

Step-by-step explanation:

Since you are given an expression for y, it is convenient to substitute that into the second equation.

  2x -3(6x +11) = 7

  2x -18x -33 = 7

  -16x = 40 . . . . . . add 33

  x = -40/16 = -2.5

Using the equation for y, we find ...

  y = 6(-2.5) +11 = -15 +11 = -4

The solution is (x, y) = (-2.5, -4).

8 0
3 years ago
Find the circumference and area of a circle with a diameter of 12 cm. (Use the approximation of 3.14 for )
MArishka [77]

Answer:

37.68 for circumference

Step-by-step explanation:

You find the circumference by doing 3.14 x diameter

6 0
3 years ago
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Please help! I'll give brainiest!
harina [27]
The answer I got was c
7 0
3 years ago
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H(x) = √x-10 Determine for each x-value whether it is in the domain of h or not.
Lesechka [4]

Answer:

0 is not in domain

5 is not in domain

10 is in domain

Step-by-step explanation:

10 is in domain because inputting 10 into the function gives an output of 0

0 is not in th domain because 0 gives us the square root of a negative number, and the quare of a negative number isnt a real number

5 is not in the domain for the same reason

5 0
3 years ago
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