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levacccp [35]
3 years ago
7

A parallelogram has coordinates of (5, 17), (10, 20). (18,9), and (13,6). Which right triangle represents one of the

Mathematics
2 answers:
liberstina [14]3 years ago
3 0
I don’t understand the question
vitfil [10]3 years ago
3 0

Answer: it's the one with the 8 and 11

Step-by-step explanation: idk trust me ‍♀️

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If 4321 - 4322 = 10 <br> Then what's 3321 - 3322 = ?
ArbitrLikvidat [17]

Answer:

10 sorry if i'm wrong

Step-by-step explanation:

8 0
3 years ago
5 is subtracted from three-fifths of x...please someone translate this expression for me.​
Fudgin [204]
3/5x-5
I believe this is the expression that is described.
8 0
3 years ago
The floor at a roller skating rink is 72.25 feet long and 51.5 feet wide. How much longer is the rink than it is wide?
Phoenix [80]
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it is 20.75 feet longer</span>
3 0
3 years ago
How do I solve problem 10?
Grace [21]

If you extend the line from 1 through the parallel line you create a transversal and a triangle.

Consecutive angles inside the parallel lines are supplementary therefor the exterior angle of the triangle on the left side measures 118 degrees. This angle creates a linear pair with the left base angle therefore that angle measures 62 degrees.

144 forms a linear pair with the right base angle of the triangle making its measure 36 degrees.

The third angle of the triangle would then measure 82 degrees. Finally this third angle forms a linear pair with angle 1 making angle 1 measure 98 degrees.

6 0
3 years ago
A 2 kg metal cylinder is supplied with 1600J of energy to heat it from 5°C to 13°C. What is the specific heat capacity of the me
Neporo4naja [7]

Answer:

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

Step-by-step explanation:

According to the First Law of Thermodynamics, the heat received by the metal cylinder is equal to the change in the internal energy. That is:

Q = \Delta U

Q = m \cdot c \cdot \Delta T

The specific heat is clear in the previous expression and finally computed:

c = \frac{Q}{m\cdot \Delta T}

c = \frac{1600\,J}{(2\,kg)\cdot (13^{\circ}C-5^{\circ}C)}

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

6 0
3 years ago
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