Answer:
And using this formula we have this:
Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917
Step-by-step explanation:
Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:
And we want to find the following probability:
And for this case we can use the cumulative distribution function given by:
And using this formula we have this:
Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917
Answer:
1.) 12000
2.) 6750
3.) 2.41
Step-by-step explanation:
Given the Equation :
f(t)=12,000(3/4)^t. ; where, t = time ; f(t) = worth of car at time, t
When, car was purchased, t = 0
t = 0
f(0) = 12000(3/4)^0
= 12000 * 1
= 12000
2.)
f(2) ; this mean the worth of the car after 2 years :
f(2)=12,000(3/4)^t.
12000(3/4)^2
12000 * 0.5625
= 6750
When car will be worth 6000
f(t) = 6000
f(t)=12,000(3/4)^t.
6000 = 12,000(3/4)^t
6000 / 12000 = (3/4)^t
1/2 = (3/4)^t
Take the log of both sides :
Log(0.5) = log(0.75)^t
log(0.5) = tlog(0.75)
- 0.301029 = - 0.124938t
t = - 0.301029 / - 0.124938
t = 2.4094
t = 2.41 years
I believe the answer is True
4/3pi *r3 = 972pi
Divide both side by pi
4/3 *r3 = 972
r3 = 972* 3/4
r3 = 729
r = the square root of 729 to the third power (I don't know if I'm expressing this correctly but answer is 9, hope you get that)
r = 9 that's your answer.
Hope it's correct, appreciate if you could let me know
