(2x - 3) (3x + 4) = 6x² + 8x - 9x - 12 = <u>6x² - x - 12 </u>
Um not fully confident which is funny because imma freshman but i believe you combined all the like terms to get “180 = 23x - 188” and it equals 180 in the end because it’s a straight line so anyways once you solve the problem you should get 16 i believe and if you’re confused just feel free to ask me and i hope i wasn’t too late to answer it
73 I believe I’m not sure
Step-by-step explanation:
5x + 2 + 3x = 8x + 2
3 + 17x + 8 = 17x + 11
19 + 6x + 2x = 8x + 19
14x + 7 + 4 = 14x + 11
9x - 3 - 7x + 4 = 2x + 1
12x + 3x - 6 - 7f = 15x - 7f - 6
14x + 7 - 3x = 11x + 7
13z + 6u + 8x + 19 - u = 13z + 5u + 8x + 19
3z + 6 + 4z + 9 + 8u = 7z + 8u + 15
2x + 8z + 13u + 6z + 4u = 2x + 14z + 17u
14y + 13x + 12y + 19x + 4 = 26y + 32x + 4
5x + 18 - 13y + 12x + 8y = 17x - 5y + 18
21v + 8 - 12v - 7 + 3t - t = 9v + 2t + 1
3t + v - t + 7v = 2t + 8v
-1 + 18x -3y + x + 9y = 19x + 6y - 1
4x + 5y + 5x + 10y = 9x + 15y
F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
