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Iteru [2.4K]
3 years ago
6

HELP ME!!! What are the three different ways you can write a ratio?

Mathematics
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

A fraction, colon, words

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1. The side view of a ramp that Jessie built for his race cars is shown below. Find r,
luda_lava [24]

Answer:

fsmsfmiomiofsmklffmkslklfmdklmsdmlkdfslkdfs

Step-by-step explanation:

8 0
3 years ago
3 thousandths + 2 hundredths is greater, less than or equal to 0.023
ValentinkaMS [17]

Answer:

Equal to

Step-by-step explanation:

I hope this helped

3 thousandths: 0.003

2 hundreths: 0.02

0.003+0.02= 0.023

4 0
4 years ago
PLEASE ANSWER
Olenka [21]

Answer:

x(1 - .4)

Step-by-step explanation:

x = regular price.

1 - .4 = .6 = 60%

The sale price is equal to the full price (aka x) minus the discounted price (40% of x = 40/100 times x =  .4x)

Therefore sale price = x - .4x or x(1 - .4)

4 0
3 years ago
In the △PQR, PQ = 39 in, PR = 17 in, and the altitude PN = 15 in. Find QR.
Licemer1 [7]

Answer:

So, this triangle PQR can be broken into two right triangles, PNQ and PNR, with legs PQ = 39, PN =15, and QN = ? and PR = 17, PN = 15, and NR =? respectively.


Let's solve for what is easier first:

Since we know that 5-15-17 is a Pythagorean triplet, we can infer that NR is 5....like I said earlier, it is a right triangle, so this guess holds true.


Here comes the interesting part:

Now, we have one part of QR, which is QN.

The other part can be solved by using the Pythagorean theorem.

It is (39^2-15^2)^(1/2)..which gives you 36, the square root of 1296, which happens to be the difference between the squares of 15 and 39.

SO, QR = QN + NR

5+36 = 41

QR = 41.

Hope this helps!

3 0
4 years ago
Read 2 more answers
find two positive even consecutive integers such that a square of the smaller integer is 10 more than the larger integer
nalin [4]

Answer:

the two positive consecutive integers are 4 and 6.

Step-by-step explanation:

Let the smaller integer be s; then s^2 = (s + 2) + 10.

Simplifying, s^2 - s - 2 - 10 = 0, or

s^2 - s - 12 = 0.

Solve this by factoring:  (s - 4)(s + 3) = 0.

Then s = 4 and s = -3.

If the first even integer is 4, the next is 6.  We omit s = -3 because it's not even.

The smaller integer is 4.  Does this satisfy the equation s^2 = (s + 2) + 10?

4^2 = (4 + 2) + 10  True or False?

16 = 6 + 10 = 16.

True.

So the two positive consecutive integers are 4 and 6.

6 0
4 years ago
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