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Marrrta [24]
3 years ago
14

Please help someone !???a

Mathematics
1 answer:
miv72 [106K]3 years ago
7 0

I think question statement c is false about proof

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The aquarium has 6 fewer yellow fish than green fish. 40 percent of the fish are yellow. How many green fish are in the aquarium
Brilliant_brown [7]
Y = number of yellow fish
G = number of green fish

Y = G - 6
Y = 0.40 * (Y+G)

G - 6 = 0.4*(G-6+G)
G - 6 = 0.4*(2G-6)
G - 6 = 0.8G -2.4
0.2G = 3.6
G = 3.6/0.2=18


There are 18 green fish.
7 0
3 years ago
PLEASEEEEE HELPPP!!! 
liubo4ka [24]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

To find the answer of this we will have to this we will have to add each of the answers together...

To find Volume of a Cylinder: π(r^2)h

To find Volume of a Cone: π(r^2)(h/3)


Givens for a Cylinder: r= 2, h=3

Givens for both Cones: r=2, h=3


Cylinder:

V= π(r^2)h

V= π(2^2)3

V= π(4)3

V= 12π


Volume of both Cones added together:

V= (π(r^2)(h/3)) * 2

V= (π(2^2)(3/3)) * 2

V= (π(4)(1)) * 2

V= (π4) * 2

V= 8π


Volume for Whole Shape:

12π + 8π = 20π cm^3


So...

The answer is: C.) 20π cm^3

5 0
3 years ago
Read 2 more answers
Christina has 2 2/3 bags of chips. She gives 2/5 of the to friend. How many bags does christina have left?
oksano4ka [1.4K]

Answer:

1  3/5 bags left

Step-by-step explanation:

If she gives 2/5 away, she keeps 3/5

3/5  *  2 2/3 = 3/5 * 8/3 =   24/15  = 1 9/15  = 1 3/5 bags left

3 0
2 years ago
The following equations are given:
jarptica [38.1K]

The solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3 and the solutions in part b hold for equation 4

<h3>Solving the variables using equations 1 and 2</h3>

There are three variables in the system

To solve the three variables, there must be at least three equations in the system of equations

Hence, the variables cannot be solved because the number of equations is not enough

<h3>Solving the variables using equations 1, 2 and 3</h3>

We have:

3x + z + y = 8

5y - x = -7

3z + 2x - 2y = 15

Make x the subject in (2)

x = 5y + 7

Substitute x = 5y + 7 in (1) and (3)

3(5y + 7) + z + y = 8

15y + 21 + z + y = 8

16y + z = -13

3z + 2(5y + 7) - 2y = 15

3z + 10y + 14 - 2y = 15

3z + 8y = 1

Multiply 16y + z = -13 by 3

48y + 3z = -39

Subtract 3z + 8y = 1 from 48y + 3z = -39

48y - 8y + 3z - 3z = -39 - 1

40y = -40

Divide by 40

y = -1

Substitute y = -1 in x = 5y + 7

x = 5(-1) + 7

x = 2

Make z the subject in 16y + z = -13

z = -13 - 16y

Substitute y = -1

z = -13 - 16(-1)

z = 3

Hence, the solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3

<h3>Can the solution work for equation 4?</h3>

We have:

4x + 5y - 2z = -3

Substitute x = 2, y = -1 and z = 3

4(2) + 5(-1) - 2(3) = -3

Evaluate

-3 = -3 --- this is true

Hence, the solutions in part b hold for equation 4

Read more about system of equations at:

brainly.com/question/12895249

#SPJ1

<u>Missing part of the question</u>

The following equations are given:

Equation #1: 3x + z + y = 8

Equation #2: 5y - x = -7

Equation #3: 3z + 2x - 2y = 15

Equation #4: 4x + 5y - 2z = -3

3 0
2 years ago
What is a unit rate?
REY [17]
A unit rate in math is the expression of a rate in a quantity of one.<span> For example, 60 miles per hour represents a commonly used unit rate. Similarly, 30 students per school bus also represents a unit rate.</span>
5 0
3 years ago
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