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3 years ago

12

The flagpole casts an 8 foot shadow as shown in the table at the same time the oak tree casts 12-foot shadow how tall is the oak

tree

1 answer:

jolli1 [7]3 years ago

3 0

How tall is the flagpole?

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if you could generate energy by fusing the hydrogen in solution a, how much of the solution would you need to generate the elect

iogann1982 [59]

Answer:

We know that:

Energy released by fusion of hydrogen in 1 liter of solution A = 7.6x10^10 J

Energy used daily in a certain family home = 3x10^4 J

(you did not write the units, so i suppose that are the same in both cases)

Then, if x is the number of liters of solution A used, the energy produced will be:

E(x) = x*7.6x10^10 J

And we want this equal to 3x10^4

then:

E(x) = x*7.6x10^10 J = 3x10^4 j

now we solve this for x.

x = (3x10^4 j)/(7.6x10^10 j) = 3.9x10^-7

Then you need to use 3.9x10^-7 L of solution a.

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3 years ago

Write the expression in radical form. b^4/5

Gnoma [55]

Answer:

$\sqrt[5]{b}^{2}$

Step-by-step explanation:

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2 years ago

What is the distance between points A and B? (Use only digits 0-9 to write the distance.)

qwelly [4]

Answer:

8

Step-by-step explanation:

A is on the negative side so you count the distanse as -6 -5 -4 so on and then you get to 0 and then its 12345678

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2 years ago

Please help please i really need help

vodomira [7]

Answer:

78

Step-by-step explanation:

help me with mine pls your smart

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3 years ago

The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

victus00 [196]

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials : n= 4

Now, the required probability will be :

$P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401$

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

5 0

2 years ago