just use what you know about this stuff
(a+36d)/(a+20d) = (a+55d)/(a+36d)
(a+36d)^2 = (a+55d)(a+20d)
a^2+72ad+1296d^2 = a^2+75ad+1100d^2
3ad = 196d^2
3a = 196d
That is, for any value of n,
a=196n
d=3n
So, there is no unique solution.
If n=1, then a=196 and d=3. The terms are
196+20*3 = 256
196+36*3 = 304
196+55*3 = 361
304/256 = 361/304
You can easily verify that it works for any value of n.
Y = mx + b
m = (0 - -5)/(6 - 3) = 5/3
y = 5/3x + b
0 = 5/3(6) + b
b = -10
(y = 5/3x - 10)3
3y = 5x - 30
3y - 5x = -30
5x - 3y = 30
Answer:
x = 71
Step-by-step explanation:
x + 25 = 96
=> x = 96 - 25
=> x = 71
If c = 8 and d = -5:
a) c - 3 = 8 - 3
= 5
b) 15 - c = 15 - 8
= 7
c) 3(c + d) = 3(8 + (-5))
= 3*3
= 9
d) 2c - 4d = 2(8) - 4(-5)
= 16 + 20
= 36
e) d - c^2 = -5 - (8)^2
= -5 - 64
= -69
f) 2d^2 + 5d = 2(-5)^2 + 5(-5)
= 50 - 25
= 25
