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3 years ago

Rewrite this equation in Slope Intercept form and

Mathematics

2 answers:

choli [55]3 years ago

6 0

Answer:

y = -2x + 6

y = 8

Step-by-step explanation:

Rewrite this equation in Slope Intercept form

2x + y = 6

Subtract 2x from both sides

y = -2x + 6

------------------------------

solve the equation at x = -1

y = -2(-1) + 6

y = 2 + 6

y = 8

german3 years ago

3 0

Answer:

y = -2x+6

y=8 when x = -1

Step-by-step explanation:

2x + y = 6

Slope intercept form is y = mx+b where m is the slope and y is the intercept

Solve for y

Subtract 2x from each side

y = -2x+6

The slope is -2 and the y intercept is -6

Let x = -1

y = -2(-1) +6

y = 2+6

y=8

(-1,8)

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What is the product of any integer and -1

mixas84 [53]

Answer:

The negative counterpart

Step-by-step explanation:

x * -1 = -x

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3 years ago

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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

D = a person has the disease

X = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

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3 years ago

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pshichka [43]

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3 years ago

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4 years ago