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tangare [24]
3 years ago
8

4x+17=23. Find the solution to this equation

Mathematics
2 answers:
Elden [556K]3 years ago
7 0

Answer:

1.5

Step-by-step explanation:

4x + 17 = 23

     - 17    -17

4x=6

then divide 4 from both sides and you get

x=1.5

ludmilkaskok [199]3 years ago
7 0

Answer:

X=1.25

Step-by-step explanation:

4x+17=23

23-17=6

4x=6

4x/4=x

6/4=1.25

X=1.25

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What is the amplitude of g(x) = 10 cos (6x - 1) – 4?
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Explain why please and make sure it is in full detail
Marysya12 [62]

Step-by-step explanation:

well,

(y - 7)² = (y - 7)(y - 7)

remember how to multiply 2 expressions ?

you have to multiply every term of one expression with every term of the other expression and sum the results all up (incl. considering their individual signs, of course).

so, when we do the multiplication, we get

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3 years ago
In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, & KM = 3x + 23, find x & the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

 KM ≅ LM

3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

               = 45 + 23

               = 68

KL = 9x - 40

    = 9(15) - 40

    = 135 - 40

    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

7 0
3 years ago
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