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3 years ago

How to solve with exponents and negatives

Mathematics

2 answers:

Oliga [24]3 years ago

8 0

multiply by negative 1

Sonbull [250]3 years ago

4 0

(-1^3+2^4)+(-1+2)^3 (-1+16)+(1)^3 15+1 16

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Jill deposited $2,500 in a savings account at a rate of 7.75%,

zloy xaker [14]

I will probably be B

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2 years ago

Circles A, B, and C overlap. x is in the overlap of circles A and B. Which of the following are true about x? Check all that app

Bond [772]

9514 1404 393

Answer:

b, c, d, e, f

Step-by-step explanation:

x ∉ A . . . . . not true, x is in A

x ∈ B . . . true

x ∉ C . . . true (x is outside the circle labeled C)

x ∈ A ⋃ B . . . true

x ∈ A ⋃ C . . . true

x ∈ A ⋂ B . . . true (x is in the overlap)

4 0

2 years ago

Read 2 more answers

I need the answer please I don't know it

Vlad1618 [11]

Basically the question is asking you for the area of the triangle.
The formula to find the area of a triangle is base x height divided by 2.
So in this case you would do 27 x 15.5 = 418.5
Now you divide by 2 (209.25)
So the answer is D. Hope this helps!!

6 0

3 years ago

Find the mean, median, mode, and range of the data below:

Inga [223]

Answer:

6.75

Step-by-step explanation:

Find the mean of the set {2,5,5,6,8,8,9,11} .

There are 8 numbers in the set. Add them all, and then divide by 8 .

2 + 5 + 5 + 6 + 8 + 8 + 9 + 118=548=6.75

3 0

2 years ago

A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3

Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = $nPk=\frac{n!}{(n-k)!}$

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = $5P4+4P2+8P3$

$=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468$

So, this can be done in 468 ways.

7 0

2 years ago